<u>136 + x + x = 180. Or, to simplify, 136 + 2x = 180. The congruent angles measure 23 degrees each.</u>
We know this because of a simple rule that goes for all triangles: The measures of all three angles in a triangle will <em>always</em> add up to 180 degrees.
One angle of a triangle measures 136 degrees. The other two angles are congruent (have the same measure).
(x stands for an unknown angle measure.) So the equation we would use is 136 + 2x = 180. We can solve this within a few steps.
1. We subtract 136 from 2x in order to isolate 2x. But if we subtract something from the left side of the equation, we have to subtract it from the right side too. Otherwise the equation will be wrong; We would be taking away the balance.
2x = 180 - 136
2. Now that 2x is isolated, we solve 180 - 136.
2x = 46
3. If we know now that 2x is equal to 46, how do we find out what x is equal to? We divide by 2 (on both sides or it'll be wrong) to get x.
2x = 46
2x/2 = 46/2
x = 23
Now we know! x = 23... The other two angles are both 23 degrees. We can check to see if that's right by solving 23 + 23 + 136... Does it add up to 180? Yes! :)
Answer:
Y=2 and x=3
Step-by-step explanation:
Since the sides are equal, 3y=x+3 and y+1=x. Solving it, we will get, y=2 and x=3
Answer:
about 0.177 mg/mL
Step-by-step explanation:
The maximum is found where the derivative of C(t) is zero.
dC/dt = 1.35e^(-2.802t) -(1.35t)2.802e^(-2.802t) = 0
Solving for t gives ...
t = 1/2.802
So, the maximum C(t) is ...
C(1/2.802) = 1.35/2.802e^(-1) ≈ 0.177 . . . . . mg/mL
The maximum average BAC during the first 6 hours is about 0.177 mg/mL.
_____
The maximum occurs about 21 minutes 25 seconds after consumption.
The answer is 11/36
2/12 chance of rolling fours
because there are 2 sides containing a four on both dice combined and 12 sides in total.
Doubles mean you have to roll the same number simultaneously so let’s say we want to calculate the probability for double ones: then it’s 1/6 on the first dice for a one, and 1/6 on the second dice to land on a one as well.
I personally like to imagine a box like this:
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If you have one dice then it’s just a random segment on one of the lines. If you want the specific result from two dice then you want two specific segments which is also the 1 specific tile out of 36 (6 width times 6 height). So you multiply.
1/6 * 1/6 = 1/36 chance to roll double of ones
And 1/36 chance to roll double twos, threes, fours, fives, and sixes. But we don’t count the double fours because any four will do. So:
1/36 * 5 = 5/36
So for the probability of either doubles or containing a four is the probability of doubles of either number plus the probability of either dice being a four:
5/36 + 2/12 =
5/36 + 6/36 =
11/36
No its not am sure its not
