Answer:
No it dose not
Step-by-step explanation:
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The answer you are looking for is a monomial
LMK if i helped x)
Answer:
y = 3.584
Step-by-step explanation:
Given
Variation = Inverse Proportional
When y = 7, x = 4
Required
Find y when x = 5
First, we need to represent the variation.
y varies inversely proportional to x³
This implies that
y ~ 1/x³
Convert variation to equation
y = k/x³
Make k the subject
k = x³y
When y = 7, x = 4
This gives:
k = 4³ * 7
k = 64 * 7
k = 448
To determine the value of y when x = 5;
We make use of y = k/x³
Substitute 5 for x and 448 for k
y = 448/5³
y = 448/125
y = 3.584


- <u>We </u><u>have </u><u>given </u><u>two </u><u>linear </u><u>equations </u><u>that</u><u> </u><u>is </u><u>2x </u><u>-</u><u> </u><u>3y </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>and </u><u>x</u><u> </u><u>+</u><u> </u><u>3y </u><u>=</u><u> </u><u>1</u><u>2</u><u> </u><u>.</u>

- <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>x </u><u>and </u><u>y </u><u>by </u><u>elimination </u><u>method</u><u>. </u>



<u>Multiply </u><u>eq(</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>by </u><u>2</u><u> </u><u>:</u><u>-</u>


<u>Subtract </u><u>eq(</u><u>1</u><u>)</u><u> </u><u>from </u><u>eq(</u><u>2</u><u>)</u><u> </u><u>:</u><u>-</u>





<u>Now</u><u>, </u><u> </u><u>Subsitute</u><u> </u><u>the </u><u>value </u><u>of </u><u>y </u><u>in </u><u>eq(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u><u>-</u>





Hence, The value of x and y is 2 and 10/3
Answer is 3,3
since x does not contain a variable move it to the right by subtracting x from both sides and multiple secou d equation by -1
y=-x+6
y=x