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3 years ago

Pls help me I’m stuck

Mathematics

1 answer:

Jet001 [13]3 years ago

6 0

Answer:

here for points thank you helped it helped

Step-by-step explanation:

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Tricky Mathy Eqaution <br><br>6/2(1+2)=

hoa [83]

Answer:

6/2(1+2)= 1

Step-by-step explanation:

First: you do what is in the parenthesis:

1 + 2 = 3

6 / 2(3)

now multiply

6 /6

now divide.

so the answer 6/2(1+2)= 1

Feel free to ask any questions and reach out for assistance/

Thank you.

4 0

3 years ago

Read 2 more answers

Which of the following is true of the location of an angle, Theta, whose tangent value is Negative StartFraction StartRoot 3 End

Anuta_ua [19.1K]

The value of theta has a 30-degree reference angle and is located in Quadrant II or IV.

Given to us

$tan \theta =-\dfrac{\sqrt{3}}{3}$

<h3>What is the value of $tan \theta =\dfrac{\sqrt{3}}{3}$ ?</h3>

To know the value $tan \theta =\dfrac{\sqrt{3}}{3}$ we will simplify the given expression,

$tan \theta =\dfrac{\sqrt{3}}{3}\\\\\\tan \theta =\dfrac{1}{\sqrt{3}}\\\\tan \theta =30^o$

Hence, the value of theta is 30°.

<h3>Finding the location of the - tan30°?</h3>

To know that the location of the -tan30°,

$tan30^o = -\dfrac{sin30^o}{cos30^o}$

As the value is negative, therefore, there can be two cases,

Case I: when the value of Sin30° is negative,

Case II: when the value of cos30° is negative.

Case I: when the value of Sin30° is negative,

If the value of Sin30° is negative, while the value of cos30° is positive, the θ will lie in the fourth quadrant.

Case II: when the value of Cos30° is negative,

If the value of Cos30° is negative, while the value of Sin30° is positive, the θ will lie in the second quadrant.

Hence, the value of theta has a 30-degree reference angle and is located in Quadrant II or IV.

Learn more about Quadrants:

brainly.com/question/350459

5 0

3 years ago

Please help me with this

Thepotemich [5.8K]

Answer:

6,561

39,204

25,575

52.5625 - 7.5625 = 45

4 0

3 years ago

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In ΔABC shown below, point A is at (0, 0), point B is at (x2, 0), point C is at (x1, y1), point D is at x sub 1 over 2, y sub 1

LenaWriter [7]

There is two ways to attempt this problem. The first is that you could prove that angle CDE is congruent to angle DAB (of which I'm not totally sure is possible) or option two. Your second choice is to prove that Line segment DE is a flat line because line segment AB is also a flat line.

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4 years ago

5 times a number is _ % increase in the number

RSB [31]

Answer:

Answer: Five times a number increased by 7 is 27 from equation Get the answers you need, now!

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3 years ago