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NISA [10]
3 years ago
14

Please help me with this

Mathematics
2 answers:
lidiya [134]3 years ago
8 0

Step-by-step explanation:

(i)

(81)^2

Use (a + b)^2 = a^2 + 2ab + b^2

(81)^2 = (80 + 1)^2 =

= 80^2 + 2 * 80 * 1 + 1^2

= 6400 + 160 + 1

= 6561

(ii)

(198)^2

Use (a - b)^2 = a^2 - 2ab + b^2

(198)^2 = (200 - 2)^2 =

= 200^2 - 2 * 200 * 2 + 2^2

= 40,000 - 800 + 4

= 39,204

(iii)

165 * 155

Use (a + b)(a - b) = a^2 - b^2

165 * 155 = (160 + 5)(160 - 5) =

= 160^2 - 5^2

= 25,600 - 25

= 25,575

(iv)

(7.25)^2 - (2.75)^2

Use a^2 - b^2 = (a + b)(a - b)

(7.25)^2 - (2.75)^2 =

= (7.25 + 2.75)(7.25 - 2.75)

= 10(4.5)

= 45

Thepotemich [5.8K]3 years ago
4 0

Answer:

6,561

39,204

25,575

52.5625 - 7.5625 = 45

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
Use the identity x3+y3+z3−3xyz=(x+y+z)(x2+y2+z2−xy−yz−zx) to determine the value of the sum of three integers given: the sum of
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x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-xy-yz-zx)

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