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skelet666 [1.2K]
3 years ago
14

Write a standard form and vertex form Vertex: (-1, 3) a = 3

Mathematics
1 answer:
vovikov84 [41]3 years ago
3 0

Answer:

f(x) = 3(x+1)^2 +3

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Identify all of the functions below.
WARRIOR [948]

Answer:

e

Step-by-step explanation:

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4 years ago
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For each set of measures, choose whether the conditions determine a unique triangle, more than one triangle, or no triangle.
Sauron [17]

Answer: 1st unique 2nd nothing 3rd more than 1

Step-by-step explanation:

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4 years ago
What is 6,588 divided by 4
nalin [4]

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1647

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1647

4

6588

4      

2 5    

2 4    

 1 8  

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Please help me now plz <br> I will mark you brainliest
elixir [45]

Answer:

theta = 24.4 degrees

Step-by-step explanation:

This is a right triangle.

sin theta = opp/ hyp

sin theta = 33/80

Take the inverse of each side

sin^-1 sin(theta) = sin^-1 (33/80)

theta =24.36197794

To the nearest tenth

theta = 24.4 degrees

6 0
3 years ago
Give the equation of a line that goes through the point ( − 21 , 2 ) and is perpendicular to the line 7 x − 4 y = − 12 . Give yo
nlexa [21]

Given:

Equation of line 7x-4y=-12.

To find:

The equation of line  that goes through the point ( − 21 , 2 ) and is perpendicular to the given line.

Solution:

The given equation of line can be written as

7x-4y+12=0

Slope of line is

\text{Slope}=-\dfrac{\text{Coefficient of x}}{\text{Coefficient of y}}

m_1=-\dfrac{7}{(-4)}

m_1=\dfrac{7}{4}

Product of slopes of two perpendicular lines is -1. So, slope of perpendicular line is

m_1m_2=-1

m_2=-\dfrac{1}{m_1}

m_2=-\dfrac{4}{7}           [\because m_1=\dfrac{7}{4}]

Now, the slope of perpendicular line is m_2=\dfrac{4}{7} and it goes through (-21,2). So, the equation of line is

y-y_1=m_2(x-x_1)

y-2=-\dfrac{4}{7}(x-(-21))

y-2=-\dfrac{4}{7}x-\dfrac{4}{7}(21)

y-2=-\dfrac{4}{7}x-12

y=-\dfrac{4}{7}x-12+2

y=-\dfrac{4}{7}x-10

Therefore, the required equation in slope intercept form is y=-\dfrac{4}{7}x-10.

7 0
4 years ago
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