Point-slope form: y-y1 = m(x-x1)
Standard form: ax + by = c
Slope-intercept form: y = mx+b
Start by finding the slope. We know it is negative since the line is decreasing. The slope is -4/3.
To create point-slope form, we need to get one point from the graph. Let's use (3,0).

To create slope-intercept form, we need the slope and the y-intercept. The y-intercept is the point where our equation crosses the y-axis. For this equation, it is 4.

To get standard form, solve the equation in terms of C.
Point-slope form: y = -4/3(x-3)
Slope-intercept form: y = -4/3x + 4
Standard form: 4/3x + y = 4
I'm pretty sure the answer to your question is -3/5 + 4/5. C.
D. -2, if the lines are parallel then the slope is the same but the y-int is different
If you would like to solve the system of linear equations, you can do this using the following steps:
2x - y = -1 ... y = 2x + 1
2x + y = -7 ... y = -7 - 2x
The correct result would be: y = 2x + 1, <span>2x + y = -7.</span>