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MatroZZZ [7]
4 years ago
12

Write 16 in exponential form.Select two answers 4^2 4^4 2^4 2^8

Mathematics
1 answer:
Ivanshal [37]4 years ago
6 0
The answer is 4^2=4 x 4= 16
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plzzzzz i vill give 5 stars a heart brainlyest if you can anwser this write 5(2j+3+1j)= using the commutive property
tatuchka [14]

Answer:

The answer would be 5 (3j + 3)

Step-by-step explanation:

The 5 outside the partheness would stay the same

2j + 1j = 3j

The 3 remains the same.

So our answer is

5(3j + 3)

5 0
3 years ago
In which career would you most likely apply<br> concepts from geometry?
sladkih [1.3K]

Answer: Construction and Engineering

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3 years ago
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Given the piecewise function shown below, select all of the statements that are true.
mars1129 [50]
When x = 1 (that is x > 0)  f(1)  = 1^2 - 1 = 0
So b is correct

7 0
4 years ago
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The output of a chemical process is continually monitored to ensure that the concentration remains within acceptable limits. Whe
marissa [1.9K]

Answer:

a)  0.31 = 31%

b) 0.03 = 3%

c) 0.36 = 36%

d) 2 times

Step-by-step explanation:

If F_X(x) is the cumulative distribution function of the random variable X, then by definition the probability P of the random variable is given by

P(X \leq x) = F_X(x)

If additionally the random variable is discrete (only has non-negative integers as outcomes as is the case in this problem) then

P(X=a)=F_X(a)-\lim_{x \to a^-}F_X(x)

a)

We are looking for P(X<2)

P(X < 2) = P(X\leq 2)-P(X=2)=F_X(2)-\lim_{x \to 2^-}F_X(x)=0.84-0.53=0.31

b)

In this case we want P(X>3)

P(X >3) = 1-P(X\leq 3)=1-F_X(3)=1-0.97=0.03

c)

Now, we are interested in P(X=1)

P(X =1) =F_X(1)-\lim_{x \to 1^-}F_X(x)=0.53-0.17=0.36

d)

The expected number of times that the process is recalibrated during the week is the expected value of the probability distribution:

P(X=1)+2P(X=2)+...+nP(X=n)+...

But it is easy to see that P(X=n) = 0 if n is an integer >4

So, the expected value is

P(X=1)+2P(X=2)+3P(X=3)+4P(X=4)

We already have P(X=1) and P(X=2). Let's compute the rest

P(X =3) =F_X(3)-\lim_{x \to 3^-}F_X(x)=0.97-0.84=0.13

P(X =4) =F_X(4)-\lim_{x \to 4^-}F_X(x)=1-0.97=0.03

and the expected value is

0.36 + 2*0.53+3*0.13+4*0.03= 1.93 = 2 times rounding to the nearest integer.

8 0
4 years ago
7X +3 equals 17: solve for x <br><br> Help!
Talja [164]
7X +3 equals 17: solve for x

Help! X= 2
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3 years ago
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