Please help is urgent
1 answer:
Answer:
x ≈ 7.2
Step-by-step explanation:
Given a tangent- secant from an external point to the circle, then
the the square of the measure of the tangent is equal to the product of the external part of the secant and the entire secant, that is
x² = 4(4 + 9) = 4 × 13 = 52 ( take the square root of both sides )
x = ≈ 7.2 ( to the nearest tenth )
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Answer:
The y-intercept is (0,0)
The x-intercepts are (-3,0), (0,0), and (4,0)
Step-by-step explanation:
So we have the function:
And we want to solve for the x- and y-intercepts.
Y)
To solve for the y-intercept, recall that the y-intercept is when the graph touches the y-axis. At that point, the x values is 0. Thus, to find the x-intercept, substitute 0 for x:
Simplify:
So, the y-intercept is (0,0)
X)
To solve for the x-intercept(s), set the function equal to 0 and solve for x:
First, factor out a negative x:
Factor within the parentheses:
Zero Product Property:
Divide by -1 on the first one. Add 4 on the second one. And subtract 3 on the right:
So, our x-intercepts are:
And we're done :)