The difference is zero if you aren't insinuating that the term, "multiple" doesn't involve exponential factors.
3•4 = 12
4•3 = 12
12
-12
___
0
However, if you are saying one multiple of 3 involves exponential powers, Then 3^4 is 81 and 4^3 is 64
4^3 = 64
64 - 81 = -17
Equal to, I think. Hope this helps.... If not sorry.
Answer:
k = 30, 
Step-by-step explanation:
Since 
is a solution, then it must satisfy the differential equation. So, we calculate the derivatives and replace the value in the equation. We have that
Then, replacing the derivatives in the equation we have:
Since 
is a positive function, we have that
.
Now, consider a general solution 
, then, by calculating the derivatives and replacing them in the equation, we get
We already know that r=5 is a solution of the equation, then we can divide the polynomial by the factor (r-5) to the get the other solution. If we do so, we get that (r-6)=0. So the other solution is r=6.
Therefore, the general solution is
Answer:
0.3 years
Step-by-step explanation:
With problems like these, I always like to start by breaking down the information into smaller pieces.
μ = 13.6
σ = 3.0
Survey of 100 self-employed people
(random variable) X = # of years of education
So now we have some notation, where μ represents population mean and σ represents population standard deviation. Hopefully, you already know that the sample mean of x-bar is the same as the population mean, so x-bar = 13.6. Now, the question asks us what the standard deviation is. Since the sample here is random, we can use the Central Limit Theorem, which allows us to guess that a distribution will be approximately normal for large sample sizes (that is, n ≥ 30). In this case, our sample size is 100, so that is satisfied. We're also told our sample is random, so we're good there, too. Now all we have to do is plug some stuff in.
The Central Limit Theorem says that for large values of n, x-bar follows an approximately normal distribution with sample mean = μ and sample standard deviation = σ/√n. So, with that info, all we need to do to find the standard deviation of x-bar is to plug our σ and n into the above formula.
σ(x-bar) = σ/√n
σ(x-bar) = 3.0/√100
σ(x-bar) = 0.3
So your answer here is .3 years.
