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agasfer [191]
3 years ago
14

Solve the equations below:

Mathematics
1 answer:
Lelu [443]3 years ago
5 0
<h2><em><u>Answ</u></em><em><u>er</u></em><em><u>:</u></em><em><u>-</u></em></h2>

<h3>1.) 3x + 2 = 15</h3>

➪ 3x = 15 - 2

➪ 3x = 13

★ \large\pink{x = \sf{\dfrac{13}{3}}}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

<h3>2.) 5x - 8 = 52</h3>

➪ 5x = 52 + 8

➪ 5x = 60

➪ x = \sf\dfrac{60}{5}

★ \large\pink{x = 12}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

<h3>3.) 2(x+1) = 14</h3>

➪ 2x + 2 = 14

➪ 2x = 14 - 2

➪ 2x = 12

➪ x = \sf\dfrac{12}{2}

★ \large\pink{x = 6}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

<h3>4.) 1/4 x + 6 = 12</h3>

➪ \sf\dfrac{1}{4} \times x = 12 - 6

➪ \sf\dfrac{1}{4} \times x = 6

➪ \sf 1 \times x = 6 \times 4

★ \large\pink{x = 24}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

<h3>5.) 1/5 + 2y = 2/5</h3>

➪ \sf 2y = \dfrac{2}{5} - \dfrac{1}{5}

➪ \sf 2y = \dfrac{2-1}{5}

➪ \sf 2y = \dfrac{1}{5}

➪ \sf y = \dfrac{1}{5 \times 2}

★ \large\pink{y = \dfrac{1}{10}}

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Solution :

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Demand for cola : 50 + 3x – 16y

Therefore, total revenue :

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In order to maximize the revenue, set

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Solving (i) and (ii),

4 x (i)    ⇒       272x - 32y = 400

     (ii)   ⇒   (-<u>)     8x - 32y = -50   </u>

                        264x        = 450

∴   $x=\frac{450}{264}=\frac{75}{44}$

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