PLEASE ANSWER ASASP FOR BRAINLEST!!!!!!!!!!!!!!!!!!!!!

the surface area of earth is about 196.9 million square miles. The land area is about 57.5 million square miles, and the rest is

kow [346]

Answer: 29.2%

Step-by-step explanation:

The total surface area is 196.9 million square miles and out of this, land occupies 57.5 million square miles.

The probability that a meteorite would hit land is the percentage of and out of the entire planet area:

= Land area/ Total earth surface area

= 57.5/ 196.9

= 29.2%

8 0

3 years ago

I need help on how to get the answer too number 27.

KiRa [710]

A^2 + b^2 = c^2
3^2 + 8^2 = c^2
9 + 64 = c^2
73 =c^2
take the square root of each side
c= 8.544

3 0

3 years ago

Which set of numbers could represent the lengths of the sides of a right triangle? 16, 32, 36 5, 12, 13 6, 7, 8 8, 12, 16

Elden [556K]

5,12,13

5X5=25

12X12=144

25+144=169

answer: square root 169=13

6 0

4 years ago

Neeed math hellppp!!!!

aleksklad [387]

Answer: A

Step by step: None

6 0

3 years ago

Read 2 more answers

An automobile manufacturer has given its van a 31.3 miles/gallon (MPG) rating. An independent testing firm has been contracted t

Fynjy0 [20]

Answer:

$z=\frac{31.1-31.3}{\frac{1.3}{\sqrt{140}}}=-1.82$

The p value for this case would be given by:

$p_v =2*P(z$

For this case since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly different from 31.3 MPG

Step-by-step explanation:

Information given

$\bar X=31.1$ represent the sample mean

$\sigma=1.3$ represent the population standard deviation

$n=140$ sample size

$\mu_o =31.3$ represent the value that we want to test

$\alpha=0.02$ represent the significance level for the hypothesis test.

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true mean is equal to 31.3 MPG, the system of hypothesis would be:

Null hypothesis: $\mu =31.3$

Alternative hypothesis: $\mu \neq 31.3$

Since we know the population deviation, the statistic is given by

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

Replacing we got:

$z=\frac{31.1-31.3}{\frac{1.3}{\sqrt{140}}}=-1.82$

The p value for this case would be given by:

$p_v =2*P(z$

For this case since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly different from 31.3 MPG

4 0

3 years ago