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Iteru [2.4K]
3 years ago
14

If A = (0,2,3,4,9,11), B = {2,3,6,8,9,10) and C= {0,2,3,9), then (A-B) n(A-C) is​

Mathematics
1 answer:
timofeeve [1]3 years ago
8 0

Answer:

(A-B)n(A-C) ={ }

<h3><em>hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em>.</em></h3>

<em>Wishing</em><em> </em><em>a</em><em> </em><em>nice</em><em> </em><em>day</em><em>.</em>

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7. If the volume of a cylinder, where the height is 3 times the radius, is 247, find the surface area of the cylinder.
lakkis [162]

Answer:

3.87987×10^5

Step-by-step explanation:

surface area of the cylinder =2πrh+2πr²

=2*π*247*3+2*π*(247)²

=3.87987×10^5

7 0
3 years ago
A literature professor decides to give a 10-questiontrue-false quiz to determine who has read an as-signed novel. She wants to c
Darya [45]

Answer:

The teacher should set the score 7 as the lowest passing grade.

Step-by-step explanation:

Let <em>X</em> = number of correct guesses.

All the questions are of true-false format.

The probability of getting a correct answer is, <em>p</em> = 0.50.

The total number of questions is, <em>n</em> = 10.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 10 and <em>p </em>= 0.50.

The probability mass function of <em>X</em> is:

P(X=x)={10\chose x}0.50^{x}(1-0.50)^{10-x};\ x=0,1,2,3...

Now the teaches chose the grading scheme such that the probability of passing a student who guesses on every question is less than 0.05.

Then the probability of failing such a students is at least 1 - 0.05 = 0.95.

Compute the probability distribution of <em>X</em>.

Consider the probability distribution attached below.

The value of <em>x</em> for which P (X ≤ x) is at least 0.95 is, <em>x</em> = 7.

So the teacher should set the score 7 as the lowest passing grade.

7 0
3 years ago
Out of 21 students in Mrs.Clarks class, 3/7 of the class are boys and 4/7 are girls. How many students in the class are girls an
lidiya [134]

Answer:

9 boys and 12 girls

Step-by-step explanation:

if you multiply the denominators by 3, you get "out of" 21. All you need to do after that is multiply the top by 3 as well and it tells you there are 9 boys and 12 girls.

8 0
3 years ago
A rectangular swimming pool is twice as long as it is wide. A small concrete walkway surrounds the pool. The walkway is a 2 feet
Ksivusya [100]

Answer:

The width and the length of the pool are 12 ft and 24 ft respectively.

Step-by-step explanation:

The length (L) of the rectangular swimming pool is twice its wide (W):

L_{1} = 2W_{1}

Also, the area of the walkway of 2 feet wide is 448:

W_{2} = 2 ft

A_{T} = W_{2}*L_{2} = 448 ft^{2}

Where 1 is for the swimming pool (lower rectangle) and 2 is for the walkway more the pool (bigger rectangle).

The total area is related to the pool area and the walkway area as follows:

A_{T} = A_{1} + A_{w}    (1)          

The area of the pool is given by:

A_{1} = L_{1}*W_{1}        

A_{1} = (2W_{1})*W_{1} = 2W_{1}^{2}  (2)          

And the area of the walkway is:

A_{w} = 2(L_{2}*2 + W_{1}*2) = 4L_{2} + 4W_{1}    (3)          

Where the length of the bigger rectangle is related to the lower rectangle as follows:                  

L_{2} = 4 + L_{1} = 4 + 2W_{1}   (4)        

By entering equations (4), (3), and (2) into equation (1) we have:

A_{T} = A_{1} + A_{w}

A_{T} = 2W_{1}^{2} + 4L_{2} + 4W_{1}                

448 = 2W_{1}^{2} + 4(4 + 2W_{1}) + 4W_{1}            

224 = W_{1}^{2} + 8 + 4W_{1} + 2W_{1}

224 = W_{1}^{2} + 8 + 6W_{1}

By solving the above quadratic equation we have:

W₁ = 12 ft

Hence, the width of the pool is 12 feet, and the length is:

L_{1} = 2W_{1} = 2*12 ft = 24 ft

Therefore, the width and the length of the pool are 12 ft and 24 ft respectively.

I hope it helps you!                                                                                          

8 0
3 years ago
if 240 slices of cake are shared into the same ration 3:5 among the boys and girls how many slices will each students recieve
OLEGan [10]
7 slices each your welcome r
6 0
2 years ago
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