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Tpy6a [65]
3 years ago
12

Al Dietrich is in training. He swims for 30 minutes, bicycles (10 mph) for 30 minutes, and runs (8 mph) for 30 minutes everyday.

How many calories is he burning with this training each day?
Mathematics
2 answers:
allochka39001 [22]3 years ago
5 0

Answer: 300 calories

Step-by-step explanation: let us assume that moving at any speed expends approximately 100 calories per mile. Moving a less-minute mile will burn a few more calories than moving a high-minute mile because of the added effort. Since the minutes for the 3 scenarios are the Same, then we can conclude that he is burning calorie at the same level in which the total equal to 300 calories

zhannawk [14.2K]3 years ago
3 0

Answer:

620

Step-by-step explanation:

(C= Calories)

8 x 20 =160c

11 x 20 =220c

12 x 20 =240c

160 + 220 + 240= 620 Calories

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Step-by-step explanation:

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3 years ago
Thomas needs to buy a cardboard sheet that will allow him to make his 224 in 3 box. To help construct the box, he decided to cut
Slav-nsk [51]

Answer:

Part 1; The volume of the box Thomas wants to make is 224 = 2·w² + 12·w

Part 2; The zeros for the equation of the function, are w = -14, or w = 8

Part 3

The width of the box is 8 inch

The length of the box, is 14 inches

The height of the box, is given as 2 inches

Part 4

Please find attached the graph of the function

Step-by-step explanation:

Part 1

The volume of the box Thomas wants to make, V = 224 in.³

The dimensions he cuts out from the length and width = 2 in² each

The length of the box = 6 inches + The width of the box

Let <em>l</em> represent the length of the box and let <em>w</em> represent the width of the box, we have;

l = 6 + w

The height of the box, h = The length of the cut out square = 2 inches

The volume of the box, V = Length, l × Width, w × Height, h

∴ V = l × w × h

l = 6 + w, h = 2

∴ V = (6 + w) × w × 2

V = 2·w² + 12·w,

The equation of the volume of the box, V = 2·w² + 12·w, where, V = 224

∴ 224 = 2·w² + 12·w

Part 2

The zeros of the equation for the volume of the box, V = 2·w² + 12·w, where, V = 224 are found as follows;

V = 224 = 2·w² + 12·w

∴ 2·w² + 12·w - 224 = 0

Dividing by 2 gives;

(2·w² + 12·w - 224)/2 = w² + 6·w - 112 = 0

∴ (w + 14) × (w - 8) = 0

The zeros for the equation of the function, are w = -14, or w = 8

Part 3

We reject the value, w = -14, therefore, the width of the box, w = 8 inch

The length of the box, l = 6 + w

∴ l = 6 + 8 = 14

The length of the box, l = 8 inches

The height of the box, <em>h</em>, is given as h = 2 inches

Part 4

The graph of the function created with MS Excel is attached

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3 years ago
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Answer:

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Step-by-step explanation:

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