Answer:
Step-by-step explanation:
<u>Slope- intercept form:</u>
<u>Given</u>
- m = -38 and point (0, 10)
As per given point, y-intercept is b = 10
<u>So the equation is:</u>
Answer:
17/7 or 2 3/7
Step-by-step explanation:
3 is the same as 21/7. Subtract 21/7-4/7 to get 17/7.
Hope it helps!
8:
A line can intersect a circle twice. So, two lines intersect one circle 4 times. Two lines can intersect two circles 8 times.
Hope this helps!
This is a little long, but it gets you there.
- ΔEBH ≅ ΔEBC . . . . HA theorem
- EH ≅ EC . . . . . . . . . CPCTC
- ∠ECH ≅ ∠EHC . . . base angles of isosceles ΔEHC
- ΔAHE ~ ΔDGB ~ ΔACB . . . . AA similarity
- ∠AEH ≅ ∠ABC . . . corresponding angles of similar triangle
- ∠AEH = ∠ECH + ∠EHC = 2∠ECH . . . external angle is equal to the sum of opposite internal angles (of ΔECH)
- ΔDAC ≅ ΔDAG . . . HA theorem
- DC ≅ DG . . . . . . . . . CPCTC
- ∠DCG ≅ ∠DGC . . . base angles of isosceles ΔDGC
- ∠BDG ≅ ∠BAC . . . .corresponding angles of similar triangles
- ∠BDG = ∠DCG + ∠DGC = 2∠DCG . . . external angle is equal to the sum of opposite internal angles (of ΔDCG)
- ∠BAC + ∠ACB + ∠ABC = 180° . . . . sum of angles of a triangle
- (∠BAC)/2 + (∠ACB)/2 + (∠ABC)/2 = 90° . . . . division property of equality (divide equation of 12 by 2)
- ∠DCG + 45° + ∠ECH = 90° . . . . substitute (∠BAC)/2 = (∠BDG)/2 = ∠DCG (from 10 and 11); substitute (∠ABC)/2 = (∠AEH)/2 = ∠ECH (from 5 and 6)
- This equation represents the sum of angles at point C: ∠DCG + ∠HCG + ∠ECH = 90°, ∴ ∠HCG = 45° . . . . subtraction property of equality, transitive property of equality. (Subtract ∠DCG+∠ECH from both equations (14 and 15).)
Answer:
5 centimetres = 1 kilometre
Step-by-step explanation:
First add up the distances measured on the map.
1.1+4.8+2.2+3.4=11.5 cm
Based on this, since the number of cm is greater than the number of km, we can figure out that each cm should not be multiplied to get the km, so we can eliminate the first two answers.
Next write an equation to represent finding the scale
x=scale
11.5=2.3x
Now solve for the scale
11.5/2.3=2.3x/2.3
5=x
Therefore the scale is 5 centimetres = 1 kilometre
