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algol [13]
3 years ago
10

The equation for the line that has a slope of −38 and passes through (0, 10) is please help me with this problem.

Mathematics
1 answer:
xenn [34]3 years ago
3 0

Answer:

  • y = -38x + 10

Step-by-step explanation:

<u>Slope- intercept form:</u>

  • y + mx = b

<u>Given</u>

  • m = -38 and point (0, 10)

As per given point, y-intercept is b = 10

<u>So the equation is:</u>

  • y = -38x + 10
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a diagram consisting of rectangles whose area is proportional to the frequency of a variable and whose width is equal to the class interval.

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5 0
3 years ago
Consider a game board that has 49 squares. You place 1 grain of wheat on the first square, 2 on the next, 4 on the next, 8 on th
Art [367]

Answer:

2^0+2^1+2^2+...+2^49

Step-by-step explanation:

1=2^0

2=2^1

4=2^2

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and so on

5 0
3 years ago
PLEASE ANSWER THESE I RLLY NEED HELP I DONT UNDERSTAND I WILL MARK YOU AS BRAINLIEST IF YOU ANSWRR CORRECTLY PLS AND TY​
faust18 [17]

Answer:

Step-by-step explanation:

5.  You are asked to write an equation of the line in slope-intercept form, so you need to determine the slope of the line and the y-intercept.

You're lucky. One of the points, (0,1), has an x-coordinate of 0, so you know that the y-intercept is 1.

Use the coordinates of the points to determine the slope of the line.

slope = (difference in y-coordinates)/(difference in x-coordinates) = (10-1)/(3-0) = 9/3 = 3

The slope-intercept equation of the line is  y = 3x+1

:::::

7. When x = 0, function A = 0 and function B = 3, so function B has a greater initial value.

7 0
3 years ago
determine whether the triangles are similar if so what is the similarity statement and the postulate or theorem used.
zmey [24]
The triangles are similar because of the SAS postulate. The sides are proportional and angle T is equal in both.
6 0
3 years ago
Hello, I am currently very stuck with this problem and I am unsure as to how I would solve it.
borishaifa [10]

We have the equation

20y=x^2-10-15

Let's complete the square, to do it let's add and subtract 25 on the right side

\begin{gathered} 20y=x^2-10-15+25-25 \\  \\ 20y=(x-5)^2-15-25_{} \\  \\ 20y=(x-5)^2-40 \\  \\  \end{gathered}

Now we can have y in function of x

\begin{gathered} y=\frac{1}{20}(x-5)^2-2 \\  \\  \end{gathered}

Now we can already identify the vertex because it's in the vertex form:

y=a(x-h)+k

Where the vertex is

(h,k)

As we can see, h = 5 and k = -2, then the vertex is

(5,-2)

Now we can continue and find the focus, the focus is

\mleft(h,k+\frac{1}{4a}\mright)

We have a = 1/20, therefore

\begin{gathered} \mleft(5,-2+5\mright) \\  \\ (5,3) \end{gathered}

The focus is

(5,3)

And the last one, the directrix, it's

y=k-\frac{1}{4a}

Then

\begin{gathered} y=-2-5 \\  \\ y=-7 \end{gathered}

Hence the correct answer is: vertex (5, -2); focus (5, 3); directrix y = -7

5 0
1 year ago
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