Answer:
Therefore the game board is divided into 81 smaller squares.
Step-by-step explanation:
Given that, there is a square game.
Consider x be length of one side the square.
The volume of the square is = side ×side
=x² square units
Since the length of side of smaller square is one-ninth of the game board.
Then one side length of the smaller square is 
units.
The area of a smaller square is 
Let a number of square is formed from the game board.
a ×The area of one smaller square= The area of game board.
According to the problem,
Therefore the game board is divided into 81 smaller squares.
Answer is B
= (-2x^2 - 2x + 1) - (x + 1)
= -2x^2 - 2x + 1 - x - 1
= -2x^2 -3x
Answer:
It will take 11 minutes per mile
Step-by-step explanation:
If he wants to run all the miles equally, just divide 55 by 5 to get an equal amount of minutes.
Answer:
r = 5.848cm, h = 11.696cm
Step-by-step explanation:
Surface area: 
Volume: 
Therefore, the height of a cylinder given its volume would be 
, thus:
We now find the derivative of the surface area of the cylinder with respect to its radius and set it equal to 0, solving for the radius:
If ![0If [tex]r>5.848](https://tex.z-dn.net/?f=0If%20%5Btex%5Dr%3E5.848)
, then the surface area of the cylinder increases
Therefore, the surface area is minimized when the radius is 
, making the minimum height 
.
In conclusion, the 2nd option is correct.
2sinxcosx - sin(2x)cos(2x) = 0
<span>Part I </span>
<span>The double angle identity for sine states that sin(2x) = 2sinxcosx </span>
<span>Thus we get: </span>
<span>sin(2x) - sin(2x)cos(2x) = 0 </span>
<span>Part II </span>
<span>sin(2x)(1 - cos(2x)) = 0 </span>
<span>Part III </span>
<span>Either sin(2x) = 0 or </span>
<span>1 - cos(2x) = 0 </span>
<span>=> cos(2x) = 1 </span>
<span>For sin(2x) = 0, this is true for </span>
<span>2x = n(pi) where n = 0, 1, 2, .... </span>
<span>x = n(pi/2) </span>
<span>For cos(2x) = 1, this is true for </span>
<span>2x = n(pi) where n = 0, 2, 4, .... </span>
<span>x = n(pi/2)
</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly.
