Answer: 0.75
Step-by-step explanation:
Given : Interval for uniform distribution : [0 minute, 5 minutes]
The probability density function will be :-
The probability that a given class period runs between 50.75 and 51.25 minutes is given by :-
![P(x>1.25)=\int^{5}_{1.25}f(x)\ dx\\\\=(0.2)[x]^{5}_{1.25}\\\\=(0.2)(5-1.25)=0.75](https://tex.z-dn.net/?f=P%28x%3E1.25%29%3D%5Cint%5E%7B5%7D_%7B1.25%7Df%28x%29%5C%20dx%5C%5C%5C%5C%3D%280.2%29%5Bx%5D%5E%7B5%7D_%7B1.25%7D%5C%5C%5C%5C%3D%280.2%29%285-1.25%29%3D0.75)
Hence, the probability that a randomly selected passenger has a waiting time greater than 1.25 minutes = 0.75
Answer:
x=12.5
Step-by-step explanation:
0.7x times (-1.4)=-3.5
-0.28x=-3.5 (divide both sides)
Ans:12.5
There are 12 inches in a foot so if there is 60 inches and you want to find how many feet it make then divide the amount of inches by 12
Answer:
-2
Step-by-step explanation:
The coefficient is the number in front of the variable.
Answer:
I'm gonna guess and I don't know. I'm gonna go with C or A
