Answer:
The sketch is provided in attached file.
0.0228
Step-by-step explanation:
The sketch is made by taking center at µ=80 and the desired probability of the mentioned area is also demonstrates.
The probability randomly selecting a score greater than 100 from this distribution can be calculated as
P(X>100)=P((X-µ)/σ > (100-80)/10)
P(X>100)=P(z>2)
P(X>100)=P(0<z<∞)-P(0<z<2)
Using normal table the probability corresponds to z-score=2 is 0.0228 and the area on the right side of normal curve is 0.5. So,
P(X>100)=0.5-0.4772=0.0228
The probability randomly selecting a score greater than 100 is 2.28%.
Answer: x - 3
Step-by-step explanation:
Factor:
2x^2 - 18
1. Factor out 2: 2(x^2 - 9)
2.Factor x^2 - 9 into (x-3)(x+3): 2(x - 3)(x + 3)
*Notice that x^2 - a^2 can always be factored into (x-a)(x+a)
where a is a constant so in this case, a is 9 which is also 3^2
so x^2 - 9 can be factored into (x - 3)(x + 3)
x^2 - 2x - 3
1. Think what two numbers multiplied together is -3 and added together is 2
-> 3 and -1 since 3(-1) = -3 and 3+ (-1) = 2
2. Factor x^2 - 2x -3 into (x - 3)(x + 1)
Therefore, since both 2x^2 - 18 and x^2 - 2x -3 do not have another common factor besides x - 3, x - 3 is the HCF of 2x^2 - 18 and x^2 - 2x -3.
You first coordinate is at positive 1 on the y axis and you second coordinate is at (7,5) on the y axis.
Answer:
x = 35
Step-by-step explanation:
AE = AC = 4.1
∠ EAD = ∠ CAB = 92° ( vertical angles are congruent )
AD = AB = 2.9
Thus by the SAS postulate
Δ AED ≅ Δ ACB, thus
∠ AED and ∠ ACB are congruent
x = 35
