Answer:

Step-by-step explanation:
Given Data,
Q=23000 J
c=4.184 J/g °c
Δt= 68 °c
m=?
By using this equation,
Q=mcΔt

Answer:
Length of garden will be 30 metres.
Step-by-step explanation:
Let the Width of garden be x metres.
then,
Length of garden will be (x+6) metres.
Area = Length × Breadth
720 = x X (c+6)
720 = x²+6x
0 = x²+6x-720
As we can see above equation is a quadratic equation in the form of ax²+bx+C.
so,

One of the Roots of the Quadratic equation is 24 and other is -30.
And as we know width of any garden cannot be negative so the width of garden will be 24 metres.
As we got the width,
adding 6 to it will give us the Length,
So,
24 metres + 6 = 30 metres.
Length of the garden is 30 metres.
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Answer:my
The height of the stack will be 9.15×10^20_m
Or 9.15×10^17_Km
Which is 6 billion times more more than the distance to the sun
Or 22.9 million times further than the star Proxima Centauri
Step-by-step explanation:
Given
Avogadro's number = 6.02×10^23 particles
And the thickness of a penny = 1.52_mm
The height of the stack will be
1.52 × 6.02 ×10^23 = 9.15×10^23_mm 9.15×10^20_m
D 22-14=8 14-7=7 7 of 14=50% so i think that’s the best estimate