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Andru [333]
2 years ago
14

An airplane traveling from chicago to LA can fly at a rate of 6 miles per minute,how many hours does it take to travel 1,200 mil

es
Mathematics
1 answer:
Allisa [31]2 years ago
8 0

Answer:

about 3 hours and 33 mins

Step-by-step explanation:

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Which of the following statements about the picture is true
Contact [7]

Answer:

  (c)  Point A is not on a bisector

Step-by-step explanation:

The figure shows you AR > AT. Since AX is the same for both triangles, angle AXR must be greater than angle AXT. This means AX is not the bisector of angle X.

Since AT is perpendicular to XT, it cannot be the perpendicular bisector of XT. That bisector will intersect XT at its midpoint, not its end.

The marked distances show you that A is different distances from T and R.

The only statement that makes any sense is ...

  Point A is not on a bisector.

7 0
2 years ago
There are 20 blueberry muffins and 15 bran muffins in a bakery.
jekas [21]
We can say that there are 20 blueberry muffins for every 15 bran muffins, according to the given information. This can be expressed as 20:15 in ratio form. We can simplify this ratio further, by dividing both sides by 5, to leave us with the simplified ratio of blueberry to bran muffins, 4:3
4 0
2 years ago
Read 2 more answers
Which of the three curves drawn matches the graph of y = 2x 2 + x?
expeople1 [14]

Answer:

y= 0 1 2 3 4

Step-by-step explanation:

just minus 2 by all of the numbers from x

6 0
2 years ago
Let φ(x, y) = arctan (y/x) .
Alexandra [31]

Answer:

a) \large F(x,y)=(-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})

b) \large \mathbb{R}^2-\{(0,0)\}

c) the points of the form (x, -x) for x≠0

Step-by-step explanation:

a)

If φ(x, y) = arctan (y/x), the vector field F = ∇φ would be

\large F(x,y)=(\frac{\partial \phi}{\partial x},\frac{\partial \phi}{\partial y})

On one hand we have,

\large \frac{\partial \phi}{\partial x}=\frac{\partial arctan(y/x)}{\partial x}=\frac{-y/x^2}{1+(y/x)^2}=-\frac{y/x^2}{1+y^2/x^2}=\\\\=-\frac{y/x^2}{(x^2+y^2)/x^2}=-\frac{y}{x^2+y^2}

On the other hand,

\large \frac{\partial \phi}{\partial y}=\frac{\partial arctan(y/x)}{\partial y}=\frac{1/x}{1+(y/x)^2}=\frac{1/x}{1+y^2/x^2}=\\\\=\frac{1/x}{(x^2+y^2)/x^2}=\frac{x}{x^2+y^2}

So

\large F(x,y)=(-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})

b)

The domain of definition of F is  

\large \mathbb{R}^2-\{(0,0)\}

i.e., all the plane X-Y except the (0,0)

c)

Here we want to find all the points such that

\large (-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})=(k,k)

where k is a real number other than 0.

But this means

\large -\frac{y}{x^2+y^2}=\frac{x}{x^2+y^2}\Rightarrow y=-x

So, all the points in the line y = -x except (0,0) are parallel to the vector field F, that is, the points (x, -x) with x≠ 0

8 0
2 years ago
8over 20= y over 60 what is y
Pachacha [2.7K]
The answer to the problem is 24
6 0
3 years ago
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