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2 years ago

Help pls...and thank you..

Mathematics

2 answers:

Allisa [31]2 years ago

6 0

Answer:

0 chance because there is no black ones but you would probably pick a yellow one bigger chance for yellow jelly bean.

Step-by-step explanation:

Gemiola [76]2 years ago

4 0

Zero because there isn’t a black jelly bean

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Divide x^3+x^2-x+2 divides by x+4

Furkat [3]

Answer:

Step-by-step explanation:

x^3 + x^2 - x + 2 \ x + 4 = x^2 -3x + 11 - 42/(x+4)

5 0

3 years ago

At First Class Pizza, 12% of the pizzas made yesterday were pepperoni pizzas. If 27 pizzas have pepperoni, how many pizzas were

gogolik [260]

Answer: 225

Step-by-step explanation:

Let the total number of pizza made be represented by x.

Therefore, the situation in the question can be written as:

12% × x = 27

12/100 × x = 27

0.12 × x = 27

0.12x = 27

Divide both side by 0.12

0.12x/0.12 = 27/0.12

x = 225

The total pizza made was 225.

3 0

2 years ago

A hardware store owner has 1,152 screws. If she wants to put them in packages of 32, how many packages can she make?

melomori [17]

Answer:

i think 36

Step-by-step explanation:

1152 / 32= 36

5 0

3 years ago

Choose the item that does NOT have a measurable volume.

Tanzania [10]

Answer:

two dimensional triangle

Step-by-step explanation:

im not smart but im pretty sure its that

4 0

2 years ago

Read 2 more answers

a line whose perpendicular distance from the origin is 4 units and the slope of perpendicular is 2÷3. Find the equation of the l

GrogVix [38]

Answer:

$\huge\boxed{y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{2}{3}x+\dfrac{4\sqrt{13}}{3}}$

Step-by-step explanation:

The equation of a line:

$y=mx+b$

We have

$m=\dfrac{2}{3}$

substitute:

$y=\dfrac{2}{3}x+b$

The formula of a distance between a point and a line:

General form of a line:

$Ax+By+C=0$

Point:

$(x_0,\ y_0)$

Distance:

$d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+b^2}}$

Convert the equation:

$y=\dfrac{2}{3}x+b$ |subtract $y$ from both sides

$\dfrac{2}{3}x-y+b=0$ |multiply both sides by 3

$2x-3y+3b=0\to A=2,\ B=-3,\ C=3b$

Coordinates of the point:

$(0,\ 0)\to x_0=0,\ y_0=0$

substitute:

$d=4$

$4=\dfrac{|2\cdot0+(-3)\cdot0+3b|}{\sqrt{2^2+(-3)^2}}\\\\4=\dfrac{|3b|}{\sqrt{4+9}}$

$4=\dfrac{|3b|}{\sqrt{13}}\qquad|$ |multiply both sides by $\sqrt{13}$

$4\sqrt{13}=|3b|\iff3b=-4\sqrt{13}\ \vee\ 3b=4\sqrt{13}$ |divide both sides by 3

$b=-\dfrac{4\sqrt{13}}{3}\ \vee\ b=\dfrac{4\sqrt{13}}{3}$

Finally:

$y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{4\sqrt{13}}{3}$

4 0

2 years ago