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3 years ago

14

At the Italian deli, the sandwich maker cut 4 2/3 lb of turkey and 9 3/5 of roast beef. How many more pounds of roast beef were

cut?

1 answer:

kherson [118]3 years ago

4 0

Answer:

4 14/15 more pounds of roast beef

Step-by-step explanation:

subtract 4 2/3 from 9 3/5

9 3/5 - 4 2/3= 4 14/15

So your answer is 4 14/15

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What is the length of the longer side in this triangle

Elena L [17]

Did you notice the little box with corners marked in the angle down at the bottom ?
That angle is a right angle, and <em>this triangle is a right triangle</em> !

This piece of information is a big help. It breaks the problem wide open.
You know that in order to find the longest side of a right triangle . . .

-- Square the length of one short side.
-- Square the length of the other short side.
-- Add the two squares together.
-- Take the square root of the sum.

One short side=48. Its square = 2,304.
The other short side=48. Its square = 2,304.
Add the two squares: 2,304 + 2,304 = 4,608

The square root of the sum = √4,608 = <em><u>67.88</u></em> (rounded)

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3 years ago

Evaluate x/y for x equals 3/10 and y equals 4/5

Over [174]

Answer:

x/y = 3/8

Step-by-step explanation:

y = 4/5 = 8/10, so ...

x/y = (3/10)/(8/10) = 3/8

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One way to divide fractions is to make them have the same denominator. Then their ratio is the ratio of their numerators.

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3 years ago

How to find imaginary zeros anf real zeros of F(x)=-4x^5-8x^3+12x

Fofino [41]

Answer:

$x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}$

Step-by-step explanation:

We are given the function:

$f(x)=-4x^5-8x^3+12x$

And we want to finds its zeros.

Therefore:

$0=-4x^5-8x^3+12x$

Firstly, we can divide everything by -4:

$0=x^5+2x^3-3x$

Factor out an x:

$0=x(x^4+2x^2-3)$

This is in quadratic form. For simplicity, we can let:

$u=x^2$

Then by substitution:

$0=x(u^2+2u-3)$

Factor:

$0=x(u+3)(u-1)$

Substitute back:

$0=x(x^2+3)(x^2-1)$

By the Zero Product Property:

$x=0\text{ and } x^2+3=0\text{ and } x^2-1=0$

Solving for each case:

$x=0\text{ and } x=\pm\sqrt{-3}\text{ and } x=\pm\sqrt{1}$

Therefore, our real and complex zeros are:

$x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}$

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2 years ago

Help please I need this now

professor190 [17]

Answer:

what is the question i cat help without the question

Step-by-step explanation:

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3 years ago

Read 2 more answers

Help with quadratic graphs asap!

zlopas [31]

x= -0.25 and 1.25

x = -0.5 and 1.5

x = 0 and 1

x = -0.375 and 1.625

Step-by-step explanation:

Given equation of the curve is

$y = 4x^2 -4x-1$

(i)

First equation $4x^2 -4x-1 =0$

Here y = 0

In x-axis the value of y = 0

The graph cuts the x-axis at(-0.25,0) and (1.25,0)

So, x= -0.25 and 1.25

(ii)

$4x^2 -4x-1 =2$

here y = 2

The line y= 2 cuts the curve at (-0.5,2) and (1.5,2)

So, x = -0.5 and 1.5

Given equation of the curve is

$y= 3x^2-3x -1$

(i)

$3x^2-3x +2 =2$

$\Leftrightarrow 3x^2-3x -1 = -1$

Here y = -1

The line y = -1 cuts the curve at (0,-1) and (1,-1)

So x = 0 and 1

(ii)

$3x^2-3x -1 =x+1$

Here y = x+1

The line y -x =1 cuts the curve at (-0.375,0.5) and (1.625,2).

So x = -0.375 and 1.625

3 0

3 years ago