The GCF of 20x^4 and 6x^3 would be " 2x^3 "
Answer:
3x^2−4x−4
Step-by-step explanation:
3x^2−8x−2+4x−2
=3x^2+−8x+−2+4x+−2
3x^2+−8x+−2+4x+−2
=(3x^2)+(−8x+4x)+(−2+−2)
=3x^2+−4x+−4
If the graph crosses the x-axis and appears almost linear at the intercept, it is a single zero. If the graph touches the x-axis and bounces off of the axis, it is a zero with even multiplicity. If the graph crosses the x-axis at a zero, it is a zero with odd multiplicity. The sum of the multiplicities is the degree