Answer:
G(3, 1), H(2, 3)
Step-by-step explanation:
When D is the midpoint of EG, it means ...
D = (E + G)/2
or
G = 2D -E = 2(3,4) -(3,7) = (2·3-3, 2·4-7) = (3, 1)
Likewise, H is ...
H = 2D -F = 2(3,4) -(4,5) = (2·3-4, 2·4-5) = (2, 3)
0.941176471 to the nearest hundredth is 0.94
Answer:
The function y = sec(x) shifted 3 units left and 7 units down .
Step-by-step explanation:
Given the function: y = sec(x)
- If k is any positive real number, then the graph of f(x) - k is the graph of y = f(x) shifted downward k units.
- If p is a positive real number, then the graph of f(x+p) is the graph of y=f(x) shifted to the left p units.
The function
comes from the base function y= sec(x).
Since 3 is added added on the inside, this is a horizontal shift Left 3 unit, and since 7 is subtracted on the outside, this is a vertical shift down 7 units.
Therefore, the transformation on the given function is shifted 3 units left and 7 units down
Answer:
The pebble will hit the ground 8.29 second after it is thrown.
Step-by-step explanation:
Given that,
The height of the pebble after t seconds is given by the equation
h= -16t²+24 t+900.
When the pebble hit the ground, the height of the pebble will be zero.
So putting h=0 in the given equation.
0 = -16t²+24 t+900
⇒-4(4t²-6t-225)=0
⇒4t²-6t-225=0
Applying quadratic formula
, here a=4, b= -6 and c= -225.

⇒ t = 8.29, -6.79
Since time can not negative.
∴t=8.29 seconds.
The pebble will hit the ground 8.29 second after it is thrown.
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