3.12 (repeating) = 3 12/99 reduces to 3 4/33 or 103/33
if there is one number repeating, like 0.222...u put that one number over 9...making it 2/9.
if there is 2 numbers repeating, like 0.1313...u put the two repeating numbers over 99...making it 13/99
if there are 3 numbers repeating, like 0.123123...u put ur three repeating numbers over 999...making it 123/999
I believe the lateral surface area is 87.96.
The equations (2) and (3) you referred to are unavailable, but it is clear that you are trying to show that two set of solutions y1 and y2, to a (second-order) differential equation are solutions, and form a fundamental set. This will be explained.
Answer:
SOLUTION OF A DIFFERENTIAL EQUATION.
Two functions y1 and y2 are set to be solutions to a differential equation if they both satisfy the said differential equation.
Suppose we have a differential equation
y'' + py' + qy = r
If y1 satisfies this differential equation, then
y1'' + py1' + qy1 = r
FUNDAMENTAL SET OF DIFFERENTIAL EQUATION.
Two functions y1 and y2 are said to form a fundamental set of solutions to a second-order differential equation if they are linearly independent. The functions are linearly independent if their Wronskian is different from zero.
If W(y1, y2) ≠ 0
Then solutions y1 and y2 form a fundamental set of the given differential equation.