Answer:
where is principal sorry I do not know
Answer:
The most correct option for the recursive expression of the geometric sequence is;
4. t₁ = 7 and tₙ = 2·tₙ₋₁, for n > 2
Step-by-step explanation:
The general form for the nth term of a geometric sequence, aₙ is given as follows;
aₙ = a₁·r⁽ⁿ⁻¹⁾
Where;
a₁ = The first term
r = The common ratio
n = The number of terms
The given geometric sequence is 7, 14, 28, 56, 112
The common ratio, r = 14/7 = 25/14 = 56/58 = 112/56 = 2
r = 2
Let, 't₁', represent the first term of the geometric sequence
Therefore, the nth term of the geometric sequence is presented as follows;
tₙ = t₁·r⁽ⁿ⁻¹⁾ = t₁·2⁽ⁿ⁻¹⁾
tₙ = t₁·2⁽ⁿ⁻¹⁾ = 2·t₁2⁽ⁿ⁻²⁾ = 2·tₙ₋₁
∴ tₙ = 2·tₙ₋₁, for n ≥ 2
Therefore, we have;
t₁ = 7 and tₙ = 2·tₙ₋₁, for n ≥ 2.
Answer:
1440 combinations ways
Step-by-step explanation:
We know that the total arrangements will be
6!= 720 because its a 6letter word
So if we take MI to be a one letter word
Same for IM
which will Also be 6!= 720
SO TOTAL possible combination will be 720+720= 1440
the bush shelter
can help you well try this method
Answer:
solution given:
volume of lower one[V1]=l×b×h=1.5×0.5×0.5=0.378m³
volume of upper one [V2]=l×b×h=1×0.5×(0.75-0.5)=
0.125m³
total volume=V1+V2=0.378m³+0.125m³=0.503m³
0.503m³ is your answer
