F(x) = [(9,11),(-11,4),(7,-6),(11,-1), (-6,-15),(-13,-5)].
egoroff_w [7]
Using the inverse functions property:
- f⁻¹(f(93)) = m = 93
- f(7) = n = -6
<h3>
How to find the values of m and n?</h3>
Two functions f(x) and f⁻¹(x) are inverses if:
f( f⁻¹(x) ) = x
f⁻¹(f(x)) = x
We want to get:
f⁻¹(f(93)) = m
By using the above definition we get:
f⁻¹(f(93)) = m = 93
Now for the second one we want:
f(7) = n
If you look at the table, you can see that f(x) contains the point (7, -6), then:
f(7) = n = -6
If you want to learn more about inverse functions:
brainly.com/question/14391067
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Answer:
x = 5
, y = 3
Step-by-step explanation:
Solve the following system:
{3 x + 4 y = 27 | (equation 1)
5 x - 3 y = 16 | (equation 2)
Swap equation 1 with equation 2:
{5 x - 3 y = 16 | (equation 1)
3 x + 4 y = 27 | (equation 2)
Subtract 3/5 × (equation 1) from equation 2:
{5 x - 3 y = 16 | (equation 1)
0 x+(29 y)/5 = 87/5 | (equation 2)
Multiply equation 2 by 5/29:
{5 x - 3 y = 16 | (equation 1)
0 x+y = 3 | (equation 2)
Add 3 × (equation 2) to equation 1:
{5 x+0 y = 25 | (equation 1)
0 x+y = 3 | (equation 2)
Divide equation 1 by 5:
{x+0 y = 5 | (equation 1)
0 x+y = 3 | (equation 2)
Collect results:
Answer: {x = 5
, y = 3
To find the percentage always multiply whatever decimal number you have by 100% <span>
1) 5 + 8 + 12 = 25 (total number in bag)
5/25 x 100% (because you're trying to find probability of red)
= 20%
2) 5 + 8 = 13 (# of red AND blue)
13/25 x 100% (divide out of the total)
=52%
3) 5/25 = 0.2 x 12/25 = 0.48 (find probability of drawing red and green)
0.2 x 0.48 x 100%
= 9.6%
4) 10 + 12 + 28 = 50 (to find total number of trials)
28/50 x 100%
= 56%
5) 5 x 7 (number of sections on first spinner multiply by # of sections on second spinner)
= 35</span><span>Its B 20%
</span>
I believe 5 marbles on the 6th line.
Line 1: 10
2: 10-1=9
3: 9-1=8
4; 8-1=7
5: 7-1=6
6: 6-1=5
Answer:
C
Step-by-step explanation:
The simplest way to solve this problem is plugging the X value back into each equation. C (y=4x+1) is the only equation that works for each set. You plug in 1 for X, you get 5 for Y. You plug in 4 for X, you get 17 for Y. Etc.