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11Alexandr11 [23.1K]
2 years ago
8

I need help lol (╯°□°)╯︵ ┻━┻​

Mathematics
1 answer:
MArishka [77]2 years ago
6 0

Answer:

b

Step-by-step explanation:

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Hey cam you guys please give me da answers
Nostrana [21]

10

Step-by-step explanation:

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2 years ago
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How do you do the distributive property for 7*7
Troyanec [42]

The distributive property: a(b + c) = ab + ac

7 × 7 = 7 × (10 - 3) = (7)(10) - (7)(3) = 70 - 21 = 49

7 × 7 = 7 × (5 + 2) = (7)(5) + (7)(2) = 35 + 14 = 49

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3 years ago
Which of the following functions has a domain of LaTeX: \left[2,7\right][ 2 , 7 ] and a range of LaTeX: \left[4,9\right][ 4 , 9
irina1246 [14]
Dbdndndndndndbbdbdbdbddbbdbdbdbdb
6 0
3 years ago
The table shows the number of words a person types of different amounts of time. What is the rate of words per minute?
Setler [38]

Answer:

<em>35 words per minute. </em>

Step-by-step explanation:

To find the answer you have to divide <em>Minutes</em> by <em>Words Typed</em>.  

105 ÷ 3 = 35.

175 ÷ 5 = 35.

315 ÷ 9 = 35.

<em>Therefore, our answer is 35.</em>

8 0
3 years ago
How many different ways can you make 82 cents using current u.s. currency
andrew11 [14]
 <span>You can probably just work it out. 

You need non-negative integer solutions to p+5n+10d+25q = 82. 

If p = leftovers, then you simply need 5n + 10d + 25q ≤ 80. 


So this is the same as n + 2d + 5q ≤ 16 

So now you simply have to "crank out" the cases. 

Case q=0 [ n + 2d ≤ 16 ] 

Case (q=0,d=0) → n = 0 through 16 [17 possibilities] 
Case (q=0,d=1) → n = 0 through 14 [15 possibilities] 
... 
Case (q=0,d=7) → n = 0 through 2 [3 possibilities] 
Case (q=0,d=8) → n = 0 [1 possibility] 

Total from q=0 case: 1 + 3 + ... + 15 + 17 = 81 

Case q=1 [ n + 2d ≤ 11 ] 
Case (q=1,d=0) → n = 0 through 11 [12] 
Case (q=1,d=1) → n = 0 through 9 [10] 
... 
Case (q=1,d=5) → n = 0 through 1 [2] 

Total from q=1 case: 2 + 4 + ... + 10 + 12 = 42 

Case q=2 [ n + 2 ≤ 6 ] 
Case (q=2,d=0) → n = 0 through 6 [7] 
Case (q=2,d=1) → n = 0 through 4 [5] 
Case (q=2,d=2) → n = 0 through 2 [3] 
Case (q=2,d=3) → n = 0 [1] 

Total from case q=2: 1 + 3 + 5 + 7 = 16 

Case q=3 [ n + 2d ≤ 1 ] 
Here d must be 0, so there is only the case: 
Case (q=3,d=0) → n = 0 through 1 [2] 

So the case q=3 only has 2. 

Grand total: 2 + 16 + 42 + 81 = 141 </span>
3 0
3 years ago
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