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olganol [36]
3 years ago
7

Una parte de 25 000 dólares se invierte al 10% de interés, otra parte al 12 % y el resto al 16%. El ingreso anual total de las t

res inversiones es de 3200 dólares. Además, el ingreso de la inversión al 16% es igual al ingreso de las otras dos inversiones combinadas. ¿Cuánto se invirtió a cada tasa de interés?
Mathematics
1 answer:
Drupady [299]3 years ago
4 0

Answer:

  • $5000 at 10%, $10000 at 12% and 10000 at 16%

Step-by-step explanation:

  • <em>One part of $ 25,000 is invested at 10% interest, another part at 12%, and the rest at 16%. The total annual income from the three investments is $ 3,200. Also, the income from the investment at 16% is equal to the income from the other two investments combined. How much was invested at each interest rate?</em>

==================

Let the parts be x, y and z

<u>As per given we get below system of equations:</u>

  • x + y + z = 25000
  • 0.1x + 0.12y + 0.16z = 3200
  • 0.1x + 0.2y = 0.16z

<u>Substitute 0.1x + 0.2y in the second equation:</u>

  • 0.16z + 0.16z = 3200
  • 0.32z = 3200
  • z = 3200/0.32
  • z = 10000

<u>Now we have:</u>

  • x + y + 10000 = 25000 ⇒ x + y = 15000

and

  • 0.1x + 0.12y + 0.16*10000 = 3200 ⇒ 0.1x + 0.12y = 1600

<u>Multiply the second equation and then subtract the first one:</u>

  • 10(0.1x + 0.12y) = 10(1600) ⇒ x + 1.2y = 16000
  • x + 1.2y - (x + y) = 16000 - 15000
  • 0.2y = 1000
  • y = 10000

Then

  • x = 15000 - 10000 = 5000

<u>So the parts are:</u>

  • $5000 at 10%, $10000 at 12% and 10000 at 16%
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Answer:

see the attachments for the two solutions

Step-by-step explanation:

When the given angle is opposite the shorter of the given sides, there will generally be two solutions. The exception is the case where the triangle is a right triangle (the ratio of the given sides is equal to the sine of the given angle). If the given angle is opposite the longer of the given sides, there is only one solution.

When a side and its opposite angle are given, as here, the law of sines can be used to solve the triangle(s). When the given angle is included between two given sides, the law of cosines can be used to solve the (one) triangle.

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A = arcsin(a/c·sin(C)) = arcsin(25/24·sin(70°)) = 78.19° or 101.81°

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