Answer:
the lower right matrix is the third correct choice
Step-by-step explanation:
Your problem statement shows that you have correctly selected the matrices representing the initial problem setup (middle left) and the problem solution (middle right).
Of the remaining matrices, the upper left is an incorrect setup, and the lower left is an incorrect solution matrix.
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We notice that in the remaining matrices on the right that the (2,3) term is 0, and the (3,2) and (3,3) terms are both 1.
The easiest way to get a 0 in the 3rd column of row 2 is to add the first row to the second. When you do that, you get ...
![\left[\begin{array}{ccc|c}1&1&1&29000\\1+2&1-3&1-1&1000(29+1)\\0&0.15&0.15&2100\end{array}\right] =\left[\begin{array}{ccc|c}1&1&1&29000\\3&-2&0&30000\\0&0.15&0.15&2100\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%261%261%2629000%5C%5C1%2B2%261-3%261-1%261000%2829%2B1%29%5C%5C0%260.15%260.15%262100%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%261%261%2629000%5C%5C3%26-2%260%2630000%5C%5C0%260.15%260.15%262100%5Cend%7Barray%7D%5Cright%5D)
Already, we see that the second row matches that in the lower right matrix.
The easiest way to get 1's in the last row is to divide that row by 0.15. When we do that, the (3,4) entry becomes 2100/0.15 = 14000, matching exactly the lower right matrix.
The correct choices here are the two you have selected, and <em>the lower right matrix</em>.
Answer:
7.8
Step-by-step explanation:
First I will try 50. I got 127,550, so that was way too big.
Let me try a smaller number. How about 5. I got 155, so that was a bit too small.
Now I'll try 20. I got 8420. Looks like the number is between 5 and 20.
How about 7. I got 399.
Let me try 8. I got 584! That's really close. It's just a little too big.
I tried 7.5, and got 485.624. So close! Just a little higher.
Putting in 7.8 yields <u>543.192!</u> That's our answer.
The previous person is correct. It’s 32x6 = 192 cm.
Answer:
Step-by-step explanation:
Stephen uses 
kilograms of tofu in each serving of his dish.
He has 
kilograms of tofu.
We want to determine how many servings Stephen can make.
To do this, we divide the total weight of tofu by the weight per serving.
Stephen can make .
Answer:
(17)
Sum of interior angles of a quadrilateral is 360°
- 110° + 130° + x + x - 3° = 360°
- 2x = 360° - 237°
- 2x = 123°
- x = 61.5°
(18)
Sum of interior angles of a hexagon is 180°*(6 - 2) = 720°
- 2*90° + 2x + 2(x + 22°) = 720°
- 90° + x + x + 22° = 360°
- 2x = 360° - 112°
- 2x = 248°
- x = 124°
(19)
Interior angles of a given pentagon are all marked as congruent, so the exterior angles are congruent too.
Sum of exterior angles is 360°.
