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mel-nik [20]
3 years ago
7

Differentiate with respect to x:y= sinh^-1(x^2+1)

Mathematics
1 answer:
Aleks [24]3 years ago
8 0

Answer:

The first derivative of y = \sinh^{-1} (x^{2}+1) is y' = \frac{2\cdot x}{\sqrt{x^{2}+2\cdot x +2}}.

Step-by-step explanation:

We proceed to find the first derivative of y = \sinh^{-1} (x^{2}+1) by explicit differentiation and rule of chain:

y = \sinh^{-1} (x^{2}+1)

y' = \frac{2\cdot x}{\sqrt{(x^{2}+1)^{2}+1}}

y' = \frac{2\cdot x}{\sqrt{x^{2}+2\cdot x +2}}

The first derivative of y = \sinh^{-1} (x^{2}+1) is y' = \frac{2\cdot x}{\sqrt{x^{2}+2\cdot x +2}}.

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