Help asap!! Simplify 2 to the 5th over 3 squared all raised to the 4th power.

Mathematics

1 answer:

aniked [119]3 years ago

4 0

Answer:

2 to the 20th power over 3 to the 12th power

Step-by-step explanation:

Numerator: base = 2. Power=5*4=20

Denominator :base 3 Power=3*4=12

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Find the area of the triangle with the given measurements. Round the solution to the nearest hundredth if necessary. B = 67°, a

kvasek [131]

Among many other formulas, the area of a triangle is

$S = \frac 1 2 a c \sin B$

where B is the angle between sides a and c.

$S=\frac 1 2(10)(20) \sin 67^\circ \approx 92.05 \textrm{ sq cm}$

Answer: 92.05 sq cm, first choice

Bonus. Here's a formula for the area S of a triangle your teacher doesn't know:

$16S^2 = 4a^2b^2 -(c^2-a^2-b^2)^2=(a^2+b^2+c^2)^2-2(a^4+b^4+c^4)$

7 0

2 years ago

I don't understand how to do this problem.

Delicious77 [7]

Answers:

x = 4
EF = 14
CF = 7
EC = 7

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Work Shown:

C is the midpoint of segment EF. This means that EC = CF. In other words, the two pieces are congruent.

Use substitution and solve for x
EC = CF
5x-13 = 3x-5
5x-13+13 = 3x-5+13
5x = 3x+8
5x-3x = 3x+8-3x
2x = 8
2x/2 = 8/2
x = 4

Now that we know that x = 4, we can use this to find EC and CF

Let's compute EC
EC = 5x - 13
EC = 5*x - 13
EC = 5*4 - 13 ... replace x with 4
EC = 20 - 13
EC = 7

Let's compute CF
CF = 3x - 5
CF = 3*x - 5
CF = 3*4 - 5 ... replace x with 4
CF = 12 - 5
CF = 7

As expected, EC = CF (both are 7 units long).

By the segment addition postulate, we can say EC+CF = EF

EC+CF = EF
EF = EC+CF
EF = 7+7
EF = 14

8 0

2 years ago

Can yall help answer this asap

Trava [24]

Answer: B

(press thanks please) i need it lol. . . . . . . . . . . . . . .

8 0

3 years ago

PLEASE HELP STAT WILL MARK BRAINLIEST.

Masja [62]

Answer:

19 r2