Answer:
f(2) = 12
f(x) = 7, x = -3, 1
Step-by-step explanation:
<u>a)</u>
plug in x as 2
f(x) = 2^2 + 2(2) + 4
f(x) = 4 + 4 + 4
f(x) = 12
<u>b)</u>
replace f(x) with 7
7 = x^2 + 2x + 4
x^2 + 2x - 3 (move 7 to other side)
Factor
ac: -3x^2
b: 2x
split b into 3x, -x
(x^2 -x) + (3x - 3)
↓ ↓
x(x-1) + 3(x-1)
Factor: (x-1)(x+3) = 0
Solve using Zero Product Property:
x - 1 = 0, x + 3 = 0
x = 1, x = -3
Answer:
the answer is n=24
Step-by-step explanation:
hope this helps :)
(-5,-1) would be the coordinates since the only thing we’re changing by moving west is that we’re subtracting from the x value. Therefore, 2-7 is -5 so we get -5,-1
Answer:
(2 x + 3) (2 x + 9)
Step-by-step explanation:
Factor the following:
4 x^2 + 24 x + 27
Factor the quadratic 4 x^2 + 24 x + 27. The coefficient of x^2 is 4 and the constant term is 27. The product of 4 and 27 is 108. The factors of 108 which sum to 24 are 6 and 18. So 4 x^2 + 24 x + 27 = 4 x^2 + 18 x + 6 x + 27 = 9 (2 x + 3) + 2 x (2 x + 3):
9 (2 x + 3) + 2 x (2 x + 3)
Factor 2 x + 3 from 9 (2 x + 3) + 2 x (2 x + 3):
Answer: (2 x + 3) (2 x + 9)
Answer:
Step-by-step explanation:
Having drawn the line, Kendall must verify that the point P belongs to the line y = 2x-1 and then calculate the distance between A-P and verify if it is the closest to A or there is another one of the line
Having the point P(3,5) substitue x to verify y
y=2*(3)-1=6-1=5 (3,5)
Now if the angle formed by A and P is 90º it means that it is the closest point, otherwise that point must be found
and we found the distance PQ and QA
; 
, 
be the APQ triangle we must find <APQ through the cosine law (graph 2).
