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ICE Princess25 [194]
3 years ago
12

I need help plz its soo hard

Mathematics
1 answer:
Alja [10]3 years ago
3 0
The answer is D. The overall number of seats equals the number of people, meaning it has to be less than 360 to follow the safety guideline
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63% of US adults opposed to taxes on junk food and soda. You randomly select 10 US adults. Find the probability that the number
WARRIOR [948]

Answer:

a) 0.0008 = 0.08% probability that the number of adults who oppose special tax on junk food and soda is exactly one.

b) 0.9644 = 96.44% probability that the number of adults who oppose special tax on junk food and soda is at least four.

c) 0.7795 = 77.95% probability that the number of adults who oppose special tax on junk food and soda is less than eight.

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they are opposed to taxes on junk food and soda, or they are not. Each adult is independent of other adults, which means that the binomial probability distribution is used to solve the question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

63% of US adults opposed to taxes on junk food and soda.

This means that p = 0.63

You randomly select 10 US adults.

This means that n = 10

(a) exactly one

This is P(X = 1). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{10,1}.(0.63)^{1}.(0.37)^{9} = 0.0008

0.0008 = 0.08% probability that the number of adults who oppose special tax on junk food and soda is exactly one.

(b) at least four

This is

P(X \geq 4) = 1 - P(X < 4)

In which

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.63)^{0}.(0.37)^{10} \approx 0

P(X = 1) = C_{10,1}.(0.63)^{1}.(0.37)^{9} = 0.0008

P(X = 2) = C_{10,2}.(0.63)^{2}.(0.37)^{8} = 0.0063

P(X = 3) = C_{10,3}.(0.63)^{3}.(0.37)^{7} = 0.0285

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0 + 0.0008 + 0.0063 + 0.0285 = 0.0356

P(X \geq 4) = 1 - P(X < 4) = 1 - 0.0356 = 0.9644

0.9644 = 96.44% probability that the number of adults who oppose special tax on junk food and soda is at least four.

(c) less than eight

This is

P(X < 8) = 1 - P(X \geq 8)

In which

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{10,8}.(0.63)^{8}.(0.37)^{2} = 0.1529

P(X = 9) = C_{10,1}.(0.63)^{9}.(0.37)^{1} = 0.0578

P(X = 10) = C_{10,2}.(0.63)^{10}.(0.37)^{0} = 0.0098

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) = 0.1529 + 0.0578 + 0.0098 = 0.2205

P(X < 8) = 1 - P(X \geq 8) = 1 - 0.2205 = 0.7795

0.7795 = 77.95% probability that the number of adults who oppose special tax on junk food and soda is less than eight.

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Use the graph of the sine function to find the values of theta for which sin theta = 0.
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<span>let y=sin theta = 0, as shown in the figure, when y=0, there are 5 values of theta, -2Pi; -Pi  0  Pi  2Pi</span>
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If x = 2 and y=-3, then -xy^2 =<br> A) -36<br> B) 18<br> C) -12<br> D) - 18
Citrus2011 [14]

Answer:

-18

Step-by-step explanation:

-xy^2 =

Let x=2 and y = -3

-(2) (-3)^2

-2 (9)

-18

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