If UT is the midsegment of QRS, then SQ = 2(2x + 2) = 4x + 4
Then,
(3x + 1)/(7x - 1) = (2x + 2)/(4x + 4) = 1/2
2(3x + 1) = 7x - 1
6x + 2 = 7x - 1
7x - 6x = 2 + 1
x = 3
Therefore, SQ = 4(3) + 4 = 12 + 4 = 16.
Sum of interior angles formula = (n-2) x 180
where n = number of sides
so,
( 19-2 ) x 180
= 17 x 180
= 3060
ans : A
hope it helps :)
Answer:

And the value for n rounded up would be n = 174
Step-by-step explanation:
We have the following info given:
previous estimation for the deviation
the margin of error desired
represent the confidence
The Margin of error is given by:

If we solve for the value of n we got:

For this problem we know that the confidence is 98% so then the significance level would be
and the critical value would be:

And replacing we got:

And the value for n rounded up would be n = 174
Answer: it’s the first one the second one and the last one
Step-by-step explanation:
Just took the quiz
7000,000+40,000+5,000+300+0+5