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2 years ago

Solve for x. Enter the solutions from least to greatest.

Mathematics

1 answer:

shepuryov [24]2 years ago

7 0

Answer:

Lesser = -7

Greater = 4

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Given the matrices: 1 2 A= 1 -1 2 1 1 B= 3 4 Calculate AB: C11 C12 [2.1] х 1 2 3 4 C21 C22 C11 = C12 = -2 C22 - C215 DONE

eduard

Answer:

$\:c_{11}=-2,\:\:\:c_{12}=-2$

$\:c_{21}=5,\:\:\:c_{22}=8$

Step-by-step explanation:

Given the matrices

$A=\begin{pmatrix}1&-1\\ 2&1\end{pmatrix}$

$B=\begin{pmatrix}1&2\\ \:3&4\end{pmatrix}$

Calculating AB:

$\begin{pmatrix}1&-1\\ \:\:2&1\end{pmatrix}\times \:\begin{pmatrix}1&2\\ \:\:3&4\end{pmatrix}=\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}$

Multiply the rows of the first matrix by the columns of the second matrix

$=\begin{pmatrix}1\cdot \:1+\left(-1\right)\cdot \:3&1\cdot \:2+\left(-1\right)\cdot \:4\\ 2\cdot \:1+1\cdot \:3&2\cdot \:2+1\cdot \:4\end{pmatrix}$

$=\begin{pmatrix}-2&-2\\ 5&8\end{pmatrix}$

Hence,

$\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}=\begin{pmatrix}-2&-2\\ \:5&8\end{pmatrix}$

Therefore,

$\:c_{11}=-2,\:\:\:c_{12}=-2$

$\:c_{21}=5,\:\:\:c_{22}=8$

5 0

2 years ago

Read 2 more answers

What is my number my number is a perfect square the only prime number in it prime factorization is 2 my number is a factor of 32

WITCHER [35]

Nmkndj;n;bnjngfndjknh;rtnh 216g6n
543646245mh.nrkjhgjn.kjgnrjkbuhjtbyultkngu;njktnj totm,my fotrtunanhioubgrviuebglryrhntonm my forytunabjvfdjkfvghyulbfwqlcbherovbegiunj gtjgbasyhj.bsf.fjkbgilhbjbhfljbvhuj

4 0

3 years ago

X+3+5x= <br> x plus three plus five x equal

choli [55]

Answer:

6x+3

Step-by-step explanation:

If you're just combining like terms this is the correct answer

5 0

2 years ago

Jim's car repair charges $50 plus $16 for every pint of oil. Sam's car repair charges $80 plus $14 for every pint of oil. At how

vova2212 [387]

Answer:

5 pints of oil for 8 dollars

Step-by-step explanation:

1.65 dollars for 1 pint

3.4/2=1.7 dollars for 1 pint

8/5=1.6 dollars for 1 pint

17.6/10=1.76 dollars for 1 pint

33/20=1.65 dollars for 1 pint

3 0

3 years ago

Quadrilateral ABCD is dilated by a scale factor of 3/2 to create quadrilateral A'B'C'D'. If quadrilateral ABCD has an area of 30

kow [346]

Answer:

67.5

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are translation, rotation, reflection and dilation.

Dilation is the enlargement or reduction of an object by a factor.

The area of ABCD = AB * BC = 30

As a result of the dilation to form A'B'C'D', A'B' = 3/2 * AB, B'C' = 3/2 * BC, C'D' = 3/2 * CD and A'D' = 3/2 * AD. Hence:

Area of A'B'C'D' = A'B' * B'C' = 3/2 * AB * 3/2 * BC = 9/4 * (AB * BC) = 9/4 * 30 = 67.5

5 0

3 years ago