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Temka [501]
3 years ago
9

1. Mrs. Gribble went to the grocery store and spent $10.80 on pizzas, $4 on apples, and $29.99 on diapers. How much money did Mr

s. Gribble spend? 2. Mrs. Bond had $100 to spend at the mall. She bought a shirt for $16.75 and a pair of shoes for $50.86. How much money does she have left? (two questions)
Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
6 0

Answer:

1. Spent $44.79

2.She has $32.39 left

Step-by-step explanation:

You might be interested in
7 1⁄5 – 6 2⁄5 = ? <br><br> A. 4⁄5<br> B. 1 4⁄5<br> C. 1 1⁄5<br> D. 13 3⁄5
STatiana [176]

Answer:

A

Step-by-step explanation:

Change the mixed numbers to improper fractions

7 \frac{1}{5} = \frac{36}{5}

6 \frac{2}{5} = \frac{32}{5}

The subtraction is then

\frac{36}{5} - \frac{32}{5}

Both fractions have a common denominator so subtract the numerators leaving the denominator

= \frac{36-32}{5} = \frac{4}{5} → A

4 0
3 years ago
The population of at a town has grown 2% each year. In 1998, the population of the town was about 10,000 people. What was the po
Nuetrik [128]

Answer:

10200

Step-by-step explanation:

This is an example of a compound interest. The equation for this problem is 10000*(1+2/100)^n. The n is the year as 1999 is 1 year away from 1998, you just replace n with 1 and you have a simple equation.

7 0
3 years ago
A movie theater has a seating capacity of 387. The theater charges $5.00 for children, $7.00 for students, and $12.00 of
Rainbow [258]

Answer:

The attendance was 198 children, 90 students and 99 adults.

Step-by-step explanation:

We define:

c: children attendance

s: students attendance

a: adult attendance

The equation that describes the total ticket sales is:

5c+7s+12a=2808

We also know that the children attendance doubles the adult attendance:

c=2a

The third equation is the seating capacity, which we assume is full:

c+s+a=387

We start by replacing variables in two of the equations:

c=2a\\\\s=387-c-a=387-2a-a=387-3a

Then, we solve the remaining equation for a:

5c+7s+12a=2808\\\\5(2a)+7(387-3a)+12a=2808\\\\10a+(2709-21a)+12a=2808\\\\10a+12a-21a=2808-2709\\\\a=99

Then, we solve for the other two equations:

c=2a=2*99=198\\\\s=387-3a=387-3*99=387-297=90

The attendance was 198 children, 90 students and 99 adults.

8 0
3 years ago
Three consecutive integers have a sum of 87. Find the integers.
ozzi

Answer:

  • 28, 29, 30

Step-by-step explanation:

<u>Let the integers be x- 1, x and x +1, then:</u>

  • x - 1 + x + x + 1 = 87
  • 3x = 87
  • x = 29

The integers are 28, 29, 30

8 0
3 years ago
Read 2 more answers
2y+7z-2z+4y+8+y+2 Combine Like Terms
Andrew [12]

Answer:

7y+5z+10

Step-by-step explanation:

7y+5z+10

8 0
3 years ago
Read 2 more answers
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