3 years ago

Please help me with this question

Mathematics

1 answer:

nydimaria [60]3 years ago

5 0

The answer is
FCG & GCF

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Let G denote the centroid of triangle ABC. If triangle ABG is equilateral with side length 2, then determine the perimeter of tr

zhannawk [14.2K]

We know from Euclidean Geometry and the properties of a centroid that GC=2GM. Now GM=sin60*GA= $\sqrt{3}$ . Hence CM=GC+GM=3* $\sqrt{3} /$ . Now, since GM is normal to AB, we have by the pythagoeran theorem that:
$AC^2=AM^2+GM^2=BM^2+GM^2=BC^2$
Hence, we calculate from this that AC^2= 28, hence AC=2* $\sqrt{7}$ =BC. Thus, the perimeter of the triangle is 2+4* $\sqrt{7}$ .

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Pepsi [2]

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kondaur [170]

Answer:

None

Step-by-step explanation:

There are actually 2 answers, 3 and -3. Although if you put it in a calculator, it would show "math error" or undefined. That's because the index is even (4) and the radicand is negative (-81)

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4 years ago

Solve for the variable x+9=12

labwork [276]

Answer:

Step-by-step explanation:

subtract 9 from both sides

x=3

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3 years ago

Read 2 more answers

3x^2/3 - 2x^1/3 - 1 = 0