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3 years ago

QUUESTION Today, everything at a store is on sale! The store offers a 20% discount.

Mathematics

1 answer:

julsineya [31]3 years ago

6 0

Answer:

(x÷100)20

Step-by-step explanation:

x÷100 would be 1% so then to find 20% you would multiply by 20

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Can't seem to get this one, help? (20pt)

egoroff_w [7]

Answer:

The answer to your question is: (∞ , 3]

Step-by-step explanation:

Remember that to express an inequality, are used ( ) and [ ].

( ) are used when the point is not consider in the interval.

[ ] are used when the point is consider or is part of the interval.

Also, an empty point indicates that the number is not consider in the interval.

and, a filled point indicates that the number is consider in the interval.

For your question, the interval will be:

(∞ , 3]

8 0

2 years ago

Don’t get it please helppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppp

UNO [17]

What do you don’t get

7 0

3 years ago

The admission fee at an amusement park is $1.50 for children and $4 for adults. On a certain day, 292 people entered the park, a

motikmotik

Answer:

112 children

180 adults

Step-by-step explanation:

Let the number of adults = A

Let the number of children = C

A + C =292

4A + 1.5C = 888. solve for A, C

A = 292 - C

4[292 - C] + 1.5C = 888

1,168 - 4C + 1.5C = 888

-2.5C = - 280

C = -280 / -2.5

C = 112 - Number of children

292 - 112 = 180 - Number of adults

6 0

2 years ago

How do I solve question 6 through 8? Solve for me

rewona [7]

The equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

<h3>How to determine the functions?</h3>

A quadratic function is represented as:

y = a(x - h)^2 + k

Question #6

The vertex of the graph is

(h, k) = (-1, 2)

So, we have:

y = a(x + 1)^2 + 2

The graph pass through the f(0) = -2

So, we have:

-2 = a(0 + 1)^2 + 2

Evaluate the like terms

a = -4

Substitute a = -4 in y = a(x + 1)^2 + 2

y = -4(x + 1)^2 + 2

Question #7

The vertex of the graph is

(h, k) = (2, 1)

So, we have:

y = a(x - 2)^2 + 1

The graph pass through (1, 3)

So, we have:

3 = a(1 - 2)^2 + 1

Evaluate the like terms

a = 2

Substitute a = 2 in y = a(x - 2)^2 + 1

y = 2(x - 2)^2 + 1

Question #8

The vertex of the graph is

(h, k) = (1, -2)

So, we have:

y = a(x - 1)^2 - 2

The graph pass through (0, -3)

So, we have:

-3 = a(0 - 1)^2 - 2

Evaluate the like terms

a = -1

Substitute a = -1 in y = a(x - 1)^2 - 2

y = -(x - 1)^2 - 2

Hence, the equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2