The equation of the line that passes through the points (1 , 4) and (-2, -5) is y = 3x + 1
<h3>Further explanation</h3>Solving linear equation mean calculating the unknown variable from the equation.
Let the linear equation : y = mx + c
If we draw the above equation on Cartesian Coordinates , it will be a straight line with :
<em>m → gradient of the line</em>
<em>( 0 , c ) → y - intercept</em>
Gradient of the line could also be calculated from two arbitrary points on line ( x₁ , y₁ ) and ( x₂ , y₂ ) with the formula :
If point ( x₁ , y₁ ) is on the line with gradient m , the equation of the line will be :
Let us tackle the problem.
Let :
(1 , 4) → (x₁ , y₁)
(-2, -5) → (x₂ , y₂)
To find the straight line equation, the following formula can be used :
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Grade: High School
Subject: Mathematics
Chapter: Linear Equations
Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point
