Given :
Miki has 104 nickels and 88 dimes.
She wants to divide her coins into groups where each group has the same number of nickels and the same number of dimes.
To Find :
Largest number of groups she can have .
Solution :
In the given question we need to find the largest number of groups she can have i.e we have to find the LCM of 104 and 88 .
Now , factorizing both of them , we get :

Form above , we can say that common factors are :

Therefore , the largest number of groups she can have is 8 .
Hence , this is the required solution .
(5/6 + 2/3) - (3/4 + 1/12
= 9/6 - 10/12
= 18/12 - 10/12
= 8/12
= SIMPLIFY: 2/3
Hope this helps!!
Answer:
4
Step-by-step explanation:
2/3 for 1 jar | meaning that: 1 jar: 1 cup (1/3 left) | 1 jar: 1 cup (1/3 left) | 1 jar: 1 cup (1/3 left) | 3/3 are left, and that makes another one (the 4th one).
Answer:
62.5 : 37.5
Step-by-step explanation:
When we divide 100 into 5:3 ratio the parts we make need to add up to 100
5parts +3 parts = 8 parts
100/8 parts = 12.5 are in each part
12.5*5 : 12.5*3
62.5 : 37.5
check our answer 62.5+37.5 = 100 ✅