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3 years ago

How many miles can a car travel on 15 gallons of gas if it travels 28 miles on 1 gallon of gas?

2 answers:

6 0

Your answer would be (D) 420

To find this you multiply the miles it can travel in 1 mile by the amount of gallons it has.

Hope this helps!

WITCHER [35]3 years ago

5 0

What is 15 times 28?

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Novosadov [1.4K]

Answer:

Step-by-step explanation:

The mean is the average of the numbers. Add up all the numbers, then divide by how many numbers there are. In other words it is the sum divided by the count.

7 + 14 + 7 + 16 + 16 = 60

60 / 5 = 12

5 0

3 years ago

What is the solution set of 4x^2 - 36 = 0?

Leto [7]

<span>4x^2 - 36 = 0 ( Original equation )

4x^2 = 36 ( Add 36 to both sides )

x^2 = 9 ( Divide by 4 on both sides )

x = 3 , -3 ( Take the square root of 9 )

Solution set: { +3 , -3 } answer is x = +3 , x = -3</span>

6 0

3 years ago

Read 2 more answers

How do I solve this?

mart [117]

X + y = 20 Substitute
x by 2 y - 4 in x + y = 20 to obtain 2 y •
4 + y = 20 Solve for y to find y = 8 and
x = 2y - 4 = 12

3 0

2 years ago

Read 2 more answers

Translate the following statement into an equation and solve for y: "y divided by 27 is-18."

Yanka [14]

Answer:

$y= -486$

Step-by-step explanation:

We first translate the statement into an equation:

$\frac{y}{27}=-18$

Then we simplify:

$y= -486$

8 0

3 years ago

Read 2 more answers

A ball is thrown from an initial height of 1 meter with an initial upward velocity of 15m/s. The ball's height h (in meters) aft

lakkis [162]

$\bf \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{h}=1+15t-5t^2}\implies \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{6}=1+15t-5t^2}\implies 0=-5+15t-5t^2 \\\\\\ ~~~~~~~~~~~~\textit{using the quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{5}t^2\stackrel{\stackrel{b}{\downarrow }}{-15}t\stackrel{\stackrel{c}{\downarrow }}{+5}=0 \qquad \qquad t= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}$

$\bf t=\cfrac{-(-15)\pm\sqrt{(-15)^2-4(5)(5)}}{2(5)}\implies t=\cfrac{15\pm\sqrt{225-100}}{10} \\\\\\ t=\cfrac{15\pm\sqrt{125}}{10}\implies t=\cfrac{15\pm\sqrt{5^2 \cdot 5}}{10}\implies t=\cfrac{\stackrel{3}{~~\begin{matrix} 15 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\pm ~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\sqrt{5}}{\underset{2}{~~\begin{matrix} 10 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}$

$\bf t=\cfrac{3\pm \sqrt{5}}{2}\implies t= \begin{cases} \frac{3+ \sqrt{5}}{2} \approx 2.618\\\\ \frac{3- \sqrt{5}}{2}\approx 0.382 \end{cases}$

8 0

3 years ago