Answer:
Step-by-step explanation:
I think the attached photo supports for your question
Here is my anser:
We need to find the slope of the of and from the graph, we see that if x increases from 2 to 4, y decreases from 4 to -2. Thus, the slope of the blue line is : 
= -3
But the slope of the perpend. bisector of the blue line is the negative reciprocal of -3, or m= 1/3.
Let's find the slope-intercept form of this bisector. We need to determine b in y=mx+b. Referring to the midpoint of the blue line, x= 3; y= 1; and m=1/3. Then
y=mx+b becomes 1=(1/3)(3) + b. Solving for b: 1=1+b. Then b=0.
Thus, the equation of the perpendicular bisector of the blue line through (3,1) is y=mx + b, or y=(1/3)x + 0, or y=x/3.
Answer:
a=9.4 b=12.0
Step-by-step explanation:
You need to use Pythagorus
So for a:
8²+5²=89 a=√89=9.4
And b:
17²-12²=145 b=√145=12.0
The probability that the aircraft is overloaded is 0.6141; since this is a greater than 50% chance, the pilot should either reduce the number of passengers on the plane or require them to reduce their baggage.
The z-score for this is given by
z = (X-μ)/σ = (169-180.2)/38 = -11.2/38 = -0.29.
Using a z-table (http://www.z-table.com) we see that the probability of weights being less than this (the area to the left of this score) is 0.3859; to find the probability that the weight is greater than this (to the right), we subtract from 1:
1-0.3859 = 0.6141.
Answer:
cost per mile = $2.
Step-by-step explanation:
Given the cost function, c(m) = 2m + 4,
Where the m represents the number of miles traveled, and $2 is the cost per mile of the cab. The $4 represents the flat rate, a set fee, or the initial value.
Therefore, the cost per mile of the cab is $2.
Answer:
Step-by-step explanation:
(1)
(2)
The initial condition is 
(3)
Infinitely many.
