In ΔIJK, i = 340 cm, ∠I=120° and ∠J=59°. Find the area of ΔIJK, to the nearest 10th of a square centimeter.
1 answer:
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Answer:
s =
Step-by-step explanation:
Given
v² = u² + 2as ( subtract u² from both sides )
v² - u² = 2as ( divide both sides by 2a )
= s
Given
v² = u² + 2as ( subtract 2as from both sides )
v² - 2as = u² ( take the square root of both sides )
± = u