6x+4=x-11
x=-3
needs to be 20 characters
Answer:
C
Step-by-step explanation:
Sorry if its wrong bro
Answer:
<u></u>
Step-by-step explanation:
Simplifying the numerator :
⇒ (-5m⁷n⁰p⁵)(2m⁴n³p²)³
⇒ (-5m⁷p⁵)(8m¹²n⁹p⁶)
⇒ (-5)(8)(m)⁷⁺¹²n⁹(p)⁵⁺⁶
⇒ <u>-40m¹⁹n⁹p¹¹</u>
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Dividing by the denominator :
⇒ 
⇒
Answer:
3(5x−11)
Step-by-step explanation:
32+15x−42
15x−33
=3(5x−11)
1
Simplify \frac{1}{2}\imath n(x+3)21ın(x+3) to \frac{\imath n(x+3)}{2}2ın(x+3)
\frac{\imath n(x+3)}{2}-\imath nx=02ın(x+3)−ınx=0
2
Add \imath nxınx to both sides
\frac{\imath n(x+3)}{2}=\imath nx2ın(x+3)=ınx
3
Multiply both sides by 22
\imath n(x+3)=\imath nx\times 2ın(x+3)=ınx×2
4
Regroup terms
\imath n(x+3)=nx\times 2\imathın(x+3)=nx×2ı
5
Cancel \imathı on both sides
n(x+3)=nx\times 2n(x+3)=nx×2
6
Divide both sides by nn
x+3=\frac{nx\times 2}{n}x+3=nnx×2
7
Subtract 33 from both sides
x=\frac{nx\times 2}{n}-3x=nnx×2−3
