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Marysya12 [62]
3 years ago
7

Please help me!! Which equation is equivalent to x + 139 = 537

Mathematics
2 answers:
const2013 [10]3 years ago
5 0

Answer:

You need to give us the answers

Step-by-step explanation:

rosijanka [135]3 years ago
4 0

But where are the equations?

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2 – 2y = 16
nekit [7.7K]

Answer:

Y = -7 and the equation would be 2 - (2 x -7) = 16

Step-by-step explanan

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3 years ago
If you have 9 people and you want to share a turkey, how much turkeys will you need?
IrinaK [193]
Well if it's a whole turkey most likely only one but if each person gets a turkey than 9
5 0
2 years ago
Match the compound inequalities
kondor19780726 [428]

I one is 8x<24 and -8≤2x-4

Hence x <24/8 =3 and -4≤2x:  divide by positive 2 to get -2≤x

Hence solution is -2≤x<3

Therefore c is the correct matching for 1.

2) 5x-2>13 or -4x≥8  

i.e. 5x>15 or x≤8/(-4) = -2 (since dividing by negative inequality reverses)

Or x>3 or x ≤-2

Hence solution is two regions to the right of 3 excluding 3 and left of -2 including -2.

Graph b is the correct match.

3) -25≤9x+2<20

Subtract 2

-27≤9x<18: Now divide by positive 9

-3≤x<2

Hence graph is the region between -3 and 2 including only -3.

Graph a is correct matching for question 3.

5 0
3 years ago
The data from the U.S. Census Bureau for 1982−2003 shows that the surface area of the United States that is covered by rural lan
Wewaii [24]
If we plug in 0 for x, we can receive the data for the year 1982. Doing so shows us that the Rural area was 1,417.4 million acres and the total area was 1,839.4 million acres. Therefore, we can conclude that the majority of the area of the United States was rural in 1982.
5 0
3 years ago
I need help , I don’t understand this
marta [7]
#2. First, we factor each polynomial. Then, if any terms on both the top and the bottom of the fraction match, they cancel out. So... we do just that. You end up with:

\frac{x(x-4)}{(x+9)(x-4)}

Notice there's an (x-4) on both top and bottom. So they cancel out. That leaves us with your answer of \frac{x}{(x+9)}

#3. We do the same thing as above then multiply and simplify. In the interest of space, I'll cut straight to some simplification. 

\frac{2(x+2)^{3} }{6x(x+2)} ( \frac{5}{(x-2)^{2} } )

Now we start cancelling. For the first fraction, there are 3 (x+2)'s on top and 1 on the bottom so we will cancel out the one on the bottom and leave 2 (x+2)'s on top. There are no more polynomials to cancel out so now we multiply across:

\frac{10(x+2)^{2} }{6x(x-2)^{2} }

10 and 6 share a GCF of 2 so we divide both of those by 2. This leaves us with the final answer of:

\frac{5(x+2)^{2} }{3x(x-2)^{2} }

#4. This equation introduces division and because of it, we must flip the second fraction to make the division sign into a multiplication symbol. Again for space, I'll flip the fraction and simplify in one step. 

\frac{3(x+2)(x-2)}{(x+4)(x-2)} ( \frac{x+4}{6(x+3)})

Now we do our cancelling. First fraction has (x - 2) in the top and bottom. They're gone. The first fraction has a (x + 4) on the bottom and the second fraction has one on the top. Those will also cancel. This leaves you with:

\frac{3(x+2)}{6(x+3)}

3 and 6 share a GCF of 3 so we divide both numbers by this. This leaves you with your final answer:

\frac{x+2}{2(x+3)}

#5. We are adding so we first factor both fractions and see what we need to multiply by to make the denominators the same. I'll do the former first. (10 - x) and (x - 10) are not the same so we multiply the first equation (top and bottom) by (x - 10) and the second equation by (10 - x). Because they will now have the same denominator we can combine them already. This gives us:

\frac{(3+2x)(x-10)+(13+x)(10-x)}{(10-x)(x-10)}

Now we FOIL each to expand and then simplify by combining like terms. Again for space, I'm just showing the result of this; you end up with:

\frac{x^{2}-20x+100}{(10-x)(x-10)}

Now we factor the top. This gives you 2 (x - 10)'s on top and one on bottom. So we just leave one on the top and cancel the bottom one out. This leaves you with your answer:

\frac{x+10}{10-x}

#6. Same process for this one so I won't repeat. I'll just show the work.

\frac{3}{(x-3)(x+2)} +  \frac{2}{(x-3)(x-2)} becomes

\frac{3(x-2) + 2(x+2)}{(x-3)(x+2)(x-2)} which equals

\frac{3x - 6 + 2x + 4}{(x-3)(x+2)(x-2)} giving you the final answer

\frac{5x - 2}{(x-3)(x+2)(x-2)}

#7. For this question we find the least common denominator to make the denominators match. For 5, x, and 2x, the LCD is 10x. So we multiply top and bottom of each fraction by what would make the bottom equal 10x. This rewrites the fraction as:

\frac{3x}{5} ( \frac{2x}{2x}) * ( \frac{5}{x}( \frac{10}{10}) -  \frac{5}{2x} ( \frac{5}{5}))

Simplify to get:

\frac{3x}{5}  * ( \frac{25}{10x})

After simplifying again, you end up with your final answer: 

\frac{3}{2}




8 0
3 years ago
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