Answer:
- The radius is r = 3 in,
- The height is h = 4 in
<u>The area of the base:</u>
- A(b) = πr² = π(3²) = 9π in²
<u>The circumference of the base:</u>
<u>The area of the lateral surface:</u>
- A(l) = Ch = 6π(4) = 24π in²
<u>The surface area:</u>
- S = 2A(b) + A(l) = 2*9π + 24π = 42π in²
<h3>
Answer: (x-10)^2 + (y-1)^2 = 25</h3>
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Explanation:
The general template of a circle is
(x-h)^2 + (y-k)^2 = r^2
Where,
- (h,k) is the center
- r is the radius
We are given (10,1) as the center so (h,k) = (10,1) meaning that h = 10 and k = 1 pair up together.
r = 5 is the given radius.
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Plug the values h = 10, k = 1, r = 5 into the equation to get:
(x-h)^2 + (y-k)^2 = r^2
(x-10)^2 + (y-1)^2 = 5^2
(x-10)^2 + (y-1)^2 = 25
A=-15
b=-5
(b+14)/a=(-5+14) / -15=9/-15=-9/15=-3/5
answer: -3/5
