Answer:
5 atoms
Explanation:
When a chemical reaction starts with 5 atoms of hydrogen, and the reaction goes into completion, it must give us 5 atoms of hydrogen.
This is in compliance with the law of conservation of mass which states that "in a chemical reaction, matter is neither created nor destroyed but converted from one form to another".
In chemical reactions, bonds are broken and new compounds are formed in the process. The same number of species at the start and end of the reaction must still be the same.
Explanation:
The given reaction at cathode will be as follows.
At cathode: , = -0.761 V
At anode: , = 0.761
Therefore, net reaction equation will be as follows.
Initial: 0.129 - - 0.427
Change: -0.047 - - -0.047
Equilibrium: (0.129 - 0.047) (0.427 - 0.047)
= 0.082 = 0.38
As for the given reaction is zero.
Hence, equation for calculating new cell potential will be as follows.
E_{cell} =
=
= 0.019
Thus, we can conclude that the cell potential of the given cell is 0.019.
1) The mass of 1 mole of virus is
2) There are 5.6 moles of viruses in an oil tanker
Explanation:
1)
One mole of a substance is the amount of that substance containing a number of particles equal to the Avogadro number:
This means that 1 mole of this virus should contain a number of virus particles equal to .
We know that the mass of 1 virus particle is
Therefore, the mass of 1 moles of viruses is equal to the mass of a single virus particle multiplied by the number of virus particles in one mole, :
2)
In this problem, we have that the mass of the oil tanker is
We also know that the mass of one mole of virus is
Therefore, we can find how many moles of viruses have a mass equal to the mass of the oil tanker by dividing the mass of the oil tanker by the mass of 1 mole of virus particles.
Mathematically, this is done by the following operation:
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Answer: Bosch process
Explanation:
Bosch process is an industrial process for the manufacture of H2. This proces uses cheap raw materials( water and coke) to generate water gas which is mixed with water in the presence of a catalyst(iron(II) oxide or chromium(iii) oxide) to generate H2