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sweet [91]
3 years ago
5

Compare the type of change that occurs when an iron bar rusts and when a substance freezes.

Chemistry
1 answer:
Ivanshal [37]3 years ago
5 0

Explanation:

when an iron bar rust is an example of a chemical change in which a new substance is formed and the change is not easily reversible.for iron to rust moisture and air must be present.while when a substance freezes,it can be easily reversed through melting and no new substance is formed.this change is termed a physical change.

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What material was added to powdered rock during tuttle and bowen's experiments?
Rzqust [24]

Answer:

water was added to powdered rock

Explanation:

4 0
3 years ago
Atoms like sodium and lithium often lose electrons, which makes them
zvonat [6]
More reactive than others
7 0
3 years ago
Read 2 more answers
What is 694,563,239 rounded to the nearest thousand
lina2011 [118]
694,563,239 rounded to the nearest thousand is 694,563.
 
It's because the first digit from the right is for ones, second for tens, third for hundreds and fourth for thousands and that's the one that we should take a closer look at. You can round it either to 3 or 4, depends on the digit of hundreds. In this case 3239 is clearly closer to 3000 than 4000, that's why we round it to 694,563, not 694,564.
6 0
3 years ago
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How many grams of Na2SO4, (molar mass =142.0 g/mol) are there in 15 mL of 0.50 m Na2SO4 solution?
ElenaW [278]

Answer:

1.1 g Na2SO4

Explanation:

First convert mL to L. Then multiply by the Molarity to get moles, then multiply by the molar mass to get grams.

15 mL x     1 L       x       0.50 mol Na2SO4     x        142 g        =          1.1 g

              10^3 mL                 1 L                                   mol                     Na2SO4

3 0
3 years ago
C=82.76% H=17.24% Molecular formula ???
san4es73 [151]

Answer:

ok

Explanation:

Element  %composition  Mol. mass  No. of C atoms  Simplest       Rounding

                                                                                           ratio             off  

C                     82.76                   12            6.89             1× 2                 2              

H                    17.24                      1              17.24              2.5× 2           5

Number of carbon atoms present =  

12

82.76

​  

=6.89

Number of hydrogen atoms present =  

1

17.24

​  

=17.24

simplest ratio =  

6.89

6.89

​  

=1  

simplest ratio =  

6.89

17.24

​  

=2.5

∴ Empirical fromula is C  

2

​  

H  

5

​  

 

Empirical formula mass= 2×12+5 = 29

∴ V.D. = 29

Mol. mass = 2 × V.D.

=58

n=  

Empiricalformulamass

Molecularmass

​  

 

=  

29

58

​  

=2

∴ Molecular formula = C  

4

​  

H  

10

​ <em>pls mark me as braillant</em>

5 0
3 years ago
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