It would be classified as decomposition reaction
Answer:
Sand has less specific heat than water.
Explanation:
Specific Heat is amount of heat needed per unit mass, to raise temperature by 1 degree celsius.
More specific heat means more heat energy needed to increase temperature. It implies - more time needed to absorb heat, increase temperature; and also more time needed to lose its heat.
Less specific heat means less heat energy needed to increase temperature. It implies - less time needed to absorb heat, increase temperature; and also less time needed to lose its heat.
Sand has less specific heat than water. So, it needs less heat absorption to increase temperature by per unit (celsius) ; than water. Hence, same level of heat to both sand & water ; increase temperature of sand more than water, & make it more hot.
Answer:
2.50 g of AlCl3
Explanation:
Goodness, stoichiometry...
So, what we need to find first is the amount of grams of AlCl3. To do this we look at the formula of molarity.
M = mols/L of solvent
So we know two parts of this formula. We have the Molarity (0.150) and the mL (125).
Now, we can't forget that we must convert 125 mL into liters so we have 0.125 L ( I forgot and had to do the entire problem again...)
So if we do the backwards equation we get:
0.150 = x/0.125
If we do math (fun ikr) we get 18.75 mols of the solution.
Now, we have to plug this wonderful number into stoichiometry
<u>0.01875 mols | 133.5 g</u>
<u>| 1 mol AgCl3</u>
If you are unfamiliar with what I'm doing, I'm basically going to multiply 0.01875*133.5 then divide that whole thing by 1.
So, I got 2.503125 g AlCl3
If your teacher is a stickler for significant figures there are 3 sig figs for this problem so your final answer should be
2.50 g of AlCl3
Hope you have a great day and fun with chemistry!!!!
1,1-hexene > 2,3,3-dimethyl-2-butene > 3-methyl-3-hexene > cis-3-hexene
The Saytzeff rule states that an alkene becomes more stable the more highly substituted it is. Since 2,3-dimethyl-2-butene is the most substituted alkene among the ones listed, it will thus be the most stable.
Ozone treatment of 2,3-dimethyl but-2-ene results in ozoinde, which with further reduction yields propanone and water. Trans-2-butene undergoes ozonolysis, producing the main ozonide. Acetaldehyde, syn- and anti-acetaldehyde oxide, and this main ozonide are the products of its breakdown.
Let's not forget that the alkenes' pi bonds are least stabilized by alkyl groups, making terminal alkenes the least stable of the group. This means that among the alkenes listed, 1-hexene is the least stable.
Learn more about 2,3-dimethyl-2-butene here brainly.com/question/24146247
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