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BlackZzzverrR [31]
3 years ago
14

Ryan has a toy car collection consisting of 160 toy cars he keeps on the wall and 340 he keeps in a display case. What percentag

e of Ryan's toy car collection does he keep on his wall?
Mathematics
1 answer:
Reika [66]3 years ago
4 0

Answer:

47%

Step-by-step explanation:

1.) 160 x 100 = 16,000

2.) 16,000 divided by 340 = 47

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Which expression is equivalent to 16^3?<br> 6^7<br> 2^11<br> 2^12<br> 2^64
ArbitrLikvidat [17]

Answer:

2^12

Step-by-step explanation:

16^3 = (2^4)^3 = 2^(4x3) = 2^12

Hope this helps!

7 0
4 years ago
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HELP 6th GRADE MATH
wlad13 [49]

Answer: What is the formula for finding the area of a triangle?

Not technically, but sometimes you may have to find the height using the Pythagorean Theorem, so if you have the hypotenuse and the base of a right triangle, the height, h = √(c^2 - b^2), so the area of the triangle could be found by A = 1/2 b √(c^2 - b^2), but it is the same principle as A = 1/2 b h.

Step-by-step explanation:

im in 6th grade to so thats easy

6 0
3 years ago
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Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro
strojnjashka [21]

Answer:

The missing side is B = 6.0\ cm

The missing angles are \alpha = 56.2 and \theta = 93.8

Step-by-step explanation:

Given

A = 10\ cm

C = 12\ cm

\beta = 30

The implication of this question is to solve for the missing side and the two missing angles

Represent

Angle A with \alpha

Angle B with \beta

Angle C with \theta

Calculating B

This will be calculated using cosine formula as thus;

B^2 = A^2 + C^2 - 2ACCos\beta

Substitute values for A, C and \beta

B^2 = 10^2 + 12^2 - 2 * 10 * 12 * Cos30

B^2 = 100 + 144 - 240 * 0.8660

B^2 = 100 + 144 - 207.8

B^2 = 36.2

Take Square root of both sides

B = \sqrt{36.2}

B = 6.0 <em>(Approximated)</em>

Calculating \alpha

This will be calculated using cosine formula as thus;

A^2 = B^2 + C^2 - 2BCCos\alpha

Substitute values for A, B and C

A^2 = B^2 + C^2 - 2BCCos\alpha

10^2 = 6^2 + 12^2 - 2 * 6 * 12 * Cos\alpha

100 = 36 + 144 - 144Cos\alpha

Collect Like Terms

100 - 36 - 144 = -144Cos\alpha

-80 = -144Cos\alpha

Divide both sides by -144

\frac{-80}{-144} = Cos\alpha

0.5556 = Cos\alpha

\alpha = cos^{-1}(0.5556)

\alpha = 56.2 <em>(Approximated)</em>

Calculating \theta

This will be calculated using cosine formula as thus;

C^2 = B^2 + A^2 - 2BACos\theta

Substitute values for A, B and C

12^2 = 6^2 + 10^2 - 2 * 6 * 10Cos\theta

144 = 36 + 100 - 120Cos\theta

Collect Like Terms

144 - 36 - 100 = -120Cos\theta

8 = -120Cos\theta

Divide both sides by -120

\frac{8}{-120} = Cos\theta

-0.0667= Cos\theta

\theta = cos^{-1}(-0.0667)

\theta = 93.8 <em>(Approximated)</em>

4 0
4 years ago
This isn geometry work :)
olya-2409 [2.1K]
1.  is the second choice 
2. is the first choice
3. is also the first choice
4. is also the first choice
5. is the last choice
6. is the second choice
7. is the first choice
8. is the last choice
9. is the second choice
10. is the last choice


your welcome brainless answer please.
3 0
4 years ago
B) Find the value of 2a? + 5b2 when a = -6 and b = 2
dedylja [7]

Answer:

2a + 5b(2)

2(-6) + 5(2)(2)

-12 + 20

=8

7 0
3 years ago
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