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Vanyuwa [196]
3 years ago
11

The scatter plot below shows the relationship between the number of hours spent jogging and the number of minutes spent stretchi

ng, by the students on a track team: A scatter plot is shown titled fitness routine. The x-axis is labeled hours jogging and the y-axis is labeled minutes stretching. Data points are located at 0 and 1, 2 and 1, 2 and 2, 4 and 3, 4 and 5, 6 and 3, 7 and 5, 9 and 4. A line connects the points 0 comma 1 and 10 comma 6. What is the y-intercept of the line of best fit, and what does it represent? 1 minute; the number of minutes students stretch when they do not jog 1 hour; the number of hours students jog when they do not stretch 4 hours; the number of hours students jog when they do not stretch 4 minutes; the number of minutes students stretch when they do not jog
Mathematics
2 answers:
kifflom [539]3 years ago
8 0

Answer:

(B) 6 hours; the number of hours students watch television when they do not exercise

Step-by-step explanation:

I JUST TOOK THE TEST

:) ;)

Juliette [100K]3 years ago
7 0
They are looking for the y intercept. The line of best fit passes the y axis at 1. the y axis is labeled minutes stretching. therefore the answer is 

A. <span>1 minute; the number of minutes students stretch when they do not jog</span>
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6 0
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\boxed{(1) \, x = \, \pm \dfrac{1}{2}, \pm 1, \pm2, \pm \dfrac{5}{2}, \pm 5, \pm 10; (2) \, x = -2}

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The Rational Roots Theorem states that, if a polynomial has any rational roots, they will have the form p/q, where p is a factor of the constant term  and q is a factor of the leading coefficient.

\text{Possible rational root} = \dfrac{ p }{ q } = \dfrac{\text{factor of constant term}}{\text{factor of leading coefficient}}

In your function, the constant term is -10 and the leading coefficient is 2, so

\text{Possible root} = \dfrac{\text{factor of 10}}{\text{factor of 2}}

Factors of 10 = ±1, ±2, ±5, ±10

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\text{Possible roots are } \large \boxed{\mathbf{x = \pm \dfrac{1}{2}, \pm 1, \pm2, \pm \dfrac{5}{2}, \pm 5, \pm 10}}

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Rather than work through all 12 possibilities, I will do one that works.

\begin{array}{r|rrrr}-2 & 2 & 6 & -1 & -10\\& & -4& -4 & 10\\& 2 & 2& -5 & 0\\\end{array}

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Since irrational roots come in pairs, the cubic equation has two real, irrational roots and one rational root at x = -2.

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