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MakcuM [25]
3 years ago
13

The height of a tree is 8 metres, correct to the nearest metre.

Mathematics
1 answer:
finlep [7]3 years ago
8 0
B or D i calculated the answer and it was between B and D
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What are the solutions to the quadratic equation x^2-16=0
maks197457 [2]
Good evening.


This is a incomplete quadratic equation, because it does not have the term bx. Therefore, we can solve this faster with the following strategy:

\mathsf{x^2 - 16 = 0}

Add 16 to both sides:

\mathsf{x^2 - 16 + 16 = 0 + 16}\\ \\ \mathsf{x^2 = 16}

Take the square root:

\mathsf{\sqrt {x^2} = \pm\sqrt{16}}\\ \\ \mathsf{\boxed{\mathsf{x = \pm4} }}

Therefore:

\boxed{\boxed{\mathsf{S=\{-4, \ +4\}}}}
4 0
4 years ago
Please help me give me right answer pleaseeeeeeeeeeee
Harlamova29_29 [7]

Answer:

7 x 2, 14, the area, then use pie, 3.14 to get the circle

Step-by-step explanation:

3 0
2 years ago
Find the least common multiple of: 12x^3y^2 and 15x^2y^5
allochka39001 [22]

Answer: 60x^3y^5

Step-by-step explanation:

Least Common Multiple :The least positive number that is a multiple of two or more numbers.

To find : The least common multiple of: 12x^3y^2 and 15x^2y^5.

Since, 12x^3y^2=2\times2\times3\times x^3y^2

15x^2y^5=3\times5\times x^2y^5

The least common multiple of: 12x^3y^2 and 15x^2y^5. = 2\times2\times3\times5\times x^3y^5=60x^3y^5 [take highest power of x and y ]

Hence, the least common multiple of: 12x^3y^2 and 15x^2y^5. = 60x^3y^5

3 0
3 years ago
Kelly spends 3/8 of her free time playing soccer. what percent of her free time was spent playing soccer?
lozanna [386]
I think it's 37.5 . I'm pretty sure cause I think you divide 3/8 . Then you go 2 to the right for your answer with the decimal. Not sure but . I think I'm right.
7 0
3 years ago
Solve the equation p^2 + 4p = 1 by completing the square.
igor_vitrenko [27]

Answer:

p = -2 ±sqrt( 5)

Step-by-step explanation:

p^2 + 4p = 1

Take the coefficient of p

4

Divide by 2

4/2 =2

Square it

2^2 = 4

Add it to each side

p^2 + 4p+4 = 1+4

(p+2) ^2 = 5

Take the square root of each side

sqrt((p+2) ^2) =±sqrt( 5)

p+2 = ±sqrt( 5)

Subtract 2 from each side

p+2-2 = -2 ±sqrt( 5)

p = -2 ±sqrt( 5)

7 0
3 years ago
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